Matlab中5D矩阵的线性化

Question

假设我有矩阵 A，在 MATLAB 中定义为：

A = zeros(2,2,2,2,2);

A(1,1,1,1,1) = 1;
A(1,1,1,1,2) = 2;
A(1,1,1,2,1) = 3;
A(1,1,1,2,2) = 4;
A(1,1,2,1,1) = 5;
A(1,1,2,1,2) = 6;
A(1,1,2,2,1) = 7;
A(1,1,2,2,2) = 8;

A(1,2,1,1,1) = 9;
A(1,2,1,1,2) = 10;
A(1,2,1,2,1) = 11;
A(1,2,1,2,2) = 12;
A(1,2,2,1,1) = 13;
A(1,2,2,1,2) = 14;
A(1,2,2,2,1) = 15;
A(1,2,2,2,2) = 16;

A(2,1,1,1,1) = 17;
A(2,1,1,1,2) = 18;
A(2,1,1,2,1) = 19;
A(2,1,1,2,2) = 20;
A(2,1,2,1,1) = 21;
A(2,1,2,1,2) = 22;
A(2,1,2,2,1) = 23;
A(2,1,2,2,2) = 24;

A(2,2,1,1,1) = 25;
A(2,2,1,1,2) = 26;
A(2,2,1,2,1) = 27;
A(2,2,1,2,2) = 28;
A(2,2,2,1,1) = 29;
A(2,2,2,1,2) = 30;
A(2,2,2,2,1) = 31;
A(2,2,2,2,2) = 32;

如何将此矩阵转换为新的矩阵 B，使矩阵 B 是一个向量，使得 B = [1,2,3,4...32]？

重塑功能不起作用，我在网上找不到任何帮助。

提前致谢！

Answer 1

您有相反顺序的尺寸来实现您想要的。所以：只需置换尺寸（使用permute）然后线性化（使用:）：

B = permute(A, [5 4 3 2 1]);
B = B(:);

如果你想在一行中，使用reshape 进行线性化：

B = reshape(permute(A, [5 4 3 2 1]), [],1);

---

如果你定义了（注意索引的反转）

A(1,1,1,1,1) = 1;
A(2,1,1,1,1) = 2;
A(1,2,1,1,1) = 3;
A(2,2,1,1,1) = 4;
A(1,1,2,1,1) = 5;
A(2,1,2,1,1) = 6;
A(1,2,2,1,1) = 7;
A(2,2,2,1,1) = 8;
...

尺寸将按“正确”顺序排列，然后您就不需要permute：

B = A(:);

或

B = reshape(A, [],1);