SQL Server：检测库存变化

Question

我有一个简单的库存表：

IF OBJECT_ID('tempdb.dbo.#t') IS NOT NULL
    DROP TABLE #t
GO

CREATE TABLE #t
(
    [date] DATE,
    Item VARCHAR(1),
    [Location] INT,
    Qty INT
)

INSERT INTO #t ([date], [Item], [Location], [Qty]) 
VALUES ('2017-11-16', 'A', 1, 5),
       ('2017-11-16', 'B', 1, 5),
       ('2017-11-16', 'B', 2, 10),
       ('2017-11-16', 'A', 3, 1),
       ('2017-11-16', 'C', 3, 2),
       ('2017-11-16', 'A', 4, 20),
       ('2017-11-15', 'A', 1, 5),
       ('2017-11-15', 'B', 1, 5),
       ('2017-11-15', 'B', 2, 10),
       ('2017-11-15', 'A', 3, 1),
       ('2017-11-15', 'C', 3, 8),
       ('2017-11-14', 'A', 1, 10),
       ('2017-11-14', 'B', 1, 1),
       ('2017-11-14', 'B', 2, 10),
       ('2017-11-14', 'A', 3, 1),
       ('2017-11-14', 'C', 3, 8)

我想找出日期（在 where 子句中）以及过去位置项目级别的数量差异。

因此结果应该如下：

+------------+------+----------+-----+------------+---------+
|    Date    | Item | Location | Qty | LastChange | LastQty |
+------------+------+----------+-----+------------+---------+
| 16.11.2017 | A    |        1 |   5 | 14.11.2017 |      10 |
| 16.11.2017 | B    |        1 |   5 | 14.11.2017 |       1 |
| 16.11.2017 | B    |        2 |  10 |            |         |
| 16.11.2017 | A    |        3 |   1 |            |         |
| 16.11.2017 | C    |        3 |   2 | 15.11.2017 |       8 |
| 16.11.2017 | A    |        4 |  20 |            |         |
+------------+------+----------+-----+------------+---------+

由于库存表很大，我想尽可能避免使用窗口函数。

我已自行加入库存表。但是，我很难找到消除不相关数据集的子句。

SELECT
    a.[date],
    a.Item,
    a.Location,
    a.qty,
    b.[date] LastChange,
    b.qty LastQty
FROM 
    #t a
LEFT JOIN 
    #t b ON a.Item = b.Item 
         AND a.location = b.location  
         AND b.date < a.date
WHERE   
    a.date = '2017-11-16'

Answer 1

您需要一个额外的LEFT JOIN 以消除冗余记录：

SELECT a.[date], a.Item, a.Location, a.qty,
       b.[date] LastChange, b.qty LastQty
FROM t AS a
LEFT JOIN t AS b 
   ON a.Item = b.Item AND a.location = b.location AND b.date < a.date AND a.qty != b.qty
LEFT JOIN t AS c 
   ON c.Item = b.Item AND c.location = b.location AND c.date < b.date    
WHERE   
    a.[date] = '2017-11-16' AND c.Item IS NULL

使用

LEFT JOIN t AS c 
   ON c.Item = b.Item AND c.location = b.location AND c.date < b.date    

结合

WHERE   
    ... AND c.Item IS NULL

就像说：给我那些b没有其他的记录，c，记录更早的日期。

Demo here

使用FIRST_VALUE窗口函数：

;WITH CTE AS (
    SELECT [date], [Item], [Location], [Qty],
           FIRST_VALUE([date]) OVER (PARTITION BY [Item], [Location] 
                                     ORDER BY [date]) AS LastChange,
           FIRST_VALUE([Qty]) OVER (PARTITION BY [Item], [Location] 
                                    ORDER BY [date]) AS LastQty
    FROM t
)
SELECT [date], [Item], [Location], [Qty],
       IIF([Qty] != [LastQty], LastChange, NULL) AS LastChange,
       IIF([Qty] != [LastQty], LastQty, NULL) AS LastQty
FROM CTE
WHERE [date] = '2017-11-16' 

Demo here

Answer 2

试试这个查询

DECLARE @ReportDate date='20171116'

SELECT
  curData.[date],
  curData.Item,
  curData.Location,
  curData.Qty,
  lastData.[date] LastChange,
  lastData.Qty LastQty
FROM
  (
    SELECT *
    FROM #t
    WHERE [date]=@ReportDate
  ) curData
OUTER APPLY
  (
    SELECT TOP 1 *
    FROM #t lastData
    WHERE lastData.Item=curData.Item
      AND lastData.Location=curData.Location
      AND lastData.[date]<curData.[date]
      AND lastData.Qty<>curData.Qty
    ORDER BY lastData.[date] DESC
  ) lastData