如何在子图之间创建空间？ [复制]

Question

标题几乎说明了一切。 我有一个包含两个子图的笔记本，并想在它们之间创建一些空间。 他们看起来彼此太近了。

Answer 1

与matplotlib.Figure.subplots_adjust:

import matplotlib.pyplot as plt

fig, (ax1, ax2) = plt.subplots(1, 2)

ax1.plot([1,2,3], [1,2,3])
ax2.plot([1,2,3], [3,2,1])
plt.show()

可以通过wspace参数来增加宽度：

... # same setup as before
fig.subplots_adjust(wspace=2)
plt.show()

如果您想对axes 的定位进行更多控制，则可以将每个轴的偏移（底部和左侧）和延伸（宽度和高度）指定为图形的百分比。

这需要一些计算才能正确：

import matplotlib.pyplot as plt

# All have the same lower border, height and width, only the distance to
# the left end of the figure differs
bottom = 0.05
height = 0.9
width = 0.15  # * 4 = 0.6 - minus the 0.1 padding 0.3 left for space
left1, left2, left3, left4 = 0.05, 0.25, 1 - 0.25 - width, 1 - 0.05 - width

rectangle1 = [left1, bottom, width, height]
rectangle2 = [left2, bottom, width, height]
rectangle3 = [left3, bottom, width, height]
rectangle4 = [left4, bottom, width, height]

# Create a 8 x 8 (quadratic) figure
plt.figure(1, figsize=(8, 8))

// Create 4 axes their position and extend is defined by the rectangles
ax1 = plt.axes(rectangle1)
ax2 = plt.axes(rectangle2)
ax3 = plt.axes(rectangle3)
ax4 = plt.axes(rectangle4)

# Let's display something in these axes.
ax1.plot([1,2,3,4])
ax2.plot([4,3,2,1])
ax3.plot([4,3,2,1])
ax4.plot([1,2,3,4])

plt.show()