当我在这个数组上使用 forEach 时，如何从数组中删除一个项目？ [复制]

Question

我有一个包含函数/对象的数组。这个对象有一个测试自己的功能，如果他们失败了，他们就会从数组中删除。如果我在这个数组上运行一个 forEach 并运行这个 testfunction 并且一个对象从数组中删除，那么 forEach 循环会跳过一个对象。

有什么好的方法可以解决这个问题？

这里是一个例子。运行该示例，您将看到在 forEach 循环中跳过了 2ed Object tests.push(new Test(2));。

//creating a test array
var tests = [];
tests.push(new Test(1));
tests.push(new Test(2));
tests.push(new Test(3));
tests.push(new Test(4));

function Test(n) {
  this.n = n;

  this.testme = function() {
    if(this.n < 3) {
	  tests.splice(tests.indexOf(this), 1); //remove me from the array tests please!
	  console.log(this.n, "I got removed!");
    } else {
      console.log(this.n, "I can stay!");
    }
  } 
}


console.log("tests length: ", tests.length);

tests.forEach(function(t) {
  t.testme();
});

console.log("tests length: ", tests.length); //output should now be 2 

Answer 1

为什么不使用内置的filter 函数？

tests = tests.filter(t => t.testMe());

Answer 2

你要做的是反向循环数组：

let i = tests.length
while(i--) tests[i].testme()

它在行动：

//creating a test array
var tests = [];
tests.push(new Test(1));
tests.push(new Test(2));
tests.push(new Test(3));
tests.push(new Test(4));

function Test(n) {
  this.n = n;

  this.testme = function() {
    if(this.n < 3) {
	  tests.splice(tests.indexOf(this), 1); //remove me from the array tests please!
	  console.log(this.n, "I got removed!");
    } else {
      console.log(this.n, "I can stay!");
    }
  } 
}


console.log("tests length: ", tests.length);

let i = tests.length
while(i--) tests[i].testme()

console.log("tests length: ", tests.length); //output should now be 2