【发布时间】:2021-07-26 17:14:31
【问题描述】:
我正在尝试使用ggplotly 将以下ggplot 图像转换为plotly:
library(tidyverse)
library(ggimage)
library(plotly)
df <- data.frame(date =
as.Date(c("01/01/1998", "10/01/1998", "15/01/1998",
"25/01/1998", "01/02/1998", "12/02/1998", "20/02/1998"), "%d/%m/%Y"),
counts = c(12, 10, 2, 24, 15, 1, 14),
image = c(NA, "https://www.r-project.org/logo/Rlogo.png", NA, NA,
"https://www.r-project.org/logo/Rlogo.png", NA, NA))
df
# date counts image
# 1 1998-01-01 12 <NA>
# 2 1998-01-10 10 https://www.r-project.org/logo/Rlogo.png
# 3 1998-01-15 2 <NA>
# 4 1998-01-25 24 <NA>
# 5 1998-02-01 15 https://www.r-project.org/logo/Rlogo.png
# 6 1998-02-12 1 <NA>
# 7 1998-02-20 14 <NA>
gg <- ggplot(df, aes(date, counts)) +
geom_line() +
geom_image(aes(image = image), size = 0.05)
gg
我无法使用 ggplotly 直接转换它,因为geom_image 没有在plotly 中实现:
ggplotly(gg, height = 700, width = 900)
# In geom2trace.default(dots[[1L]][[1L]], dots[[2L]][[1L]], dots[[3L]][[1L]]) :
# geom_GeomImage() has yet to be implemented in plotly.
# If you'd like to see this geom implemented,
# Please open an issue with your example code at
# https://github.com/ropensci/plotly/issues
我认为您需要通过删除geom_image 并在layout 中添加图像来采取不同的方式。我不知道如何引用图像应该通过的位置(即df$image)。
即使手动操作,我也无法在图表上获得一张图片:
gg2 <- ggplot(df, aes(date, counts)) +
geom_line()
ggplotly(gg2, height = 700, width = 900) %>%
layout(
images = list(
list(source = "https://www.r-project.org/logo/Rlogo.png",
xref = "paper", #https://plotly.com/r/reference/
yref = "paper",
x = .2, #as.Date(c("10/01/1998"), "%d/%m/%Y"),
y = .2,
sizex = 0.1,
sizey = 0.1,
opacity = 0.8
)))
这个solution 建议我需要以不同的日期格式工作,但我也无法让它工作:
ggplotly(gg2, height = 700, width = 900) %>%
layout(
images = list(
list(source = "https://www.r-project.org/logo/Rlogo.png",
xref = "x", #or paper
yref = "y", #or paper
x = as.numeric(as.POSIXct("10/01/1998", format = "%d/%m/%Y")), #or .3
y = 10, #or .4
sizex = 0.1,
sizey = 0.1,
opacity = 0.8
)))
#or, reformat the x axis first
ggplotly(gg2, height = 700, width = 900) %>%
layout(xaxis = list(range =
c(as.numeric(as.POSIXct("01/01/1998", format="%d/%m/%Y"))*1000,
as.numeric(as.POSIXct("20/02/1998", format="%d/%m/%Y"))*1000),
type = "date"),
images = list(
list(source = "https://www.r-project.org/logo/Rlogo.png",
xref = "x",
yref = "y",
x = as.numeric(as.POSIXct("10/01/1998", format="%d/%m/%Y"))*1000,
y = 10,
sizex = 0.1,
sizey = 0.1,
opacity = 0.8
)))
#converting date from the outset using as.POSIXct doesn't help
#df$date <- as.numeric(as.POSIXct(df$date, format="%d/%m/%Y"))*1000
任何灵活的建议允许我参考我想要图像的所有点?
谢谢
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