【发布时间】:2019-10-22 05:58:23
【问题描述】:
我正在学习如何使用 purrr,并认为它对跟踪一些计算很有用。
但是,我不确定为什么我不能使用涉及以下组件的 purrr::pmap 执行特定操作:
列出每个长度为 n 的元素 长度为 1 的向量 长度为 1 的向量 长度为 n 的向量 1.、2. 和 3. 都在同一个数据框中(名为“操作_df”)。 4. 在数据框之外,但是是每个列表元素的长度相同的向量(它们的长度都相同)。所以函数调用基本上涉及将 1. 的向量中的每个元素乘以 4. 中的每个元素,然后用 2 和 3 加/减得到的 1 元素向量。
如果我用 map2 函数分解事情,这很好用。但我想知道如何让它与 pmap 一起工作?
library(purrr)
library(dplyr)
#>
#> Attaching package: 'dplyr'
#> The following objects are masked from 'package:stats':
#>
#> filter, lag
#> The following objects are masked from 'package:base':
#>
#> intersect, setdiff, setequal, union
# generate data
data <- rbeta(n = 10, shape1 = 80, shape2 = 80)
prob_k1 <- rbeta(n = 10, shape1 = 80, shape2 = 10)
prob_k2 <- 1-prob_k1
# perform operations on prob_k and data in a data.frame
operations_df <- tibble(components = c('1', '2'),
probability = list(prob_k1, prob_k2)) %>%
# sum over list column
mutate(n = map_dbl(probability, sum)) %>%
# mean for each row, using list column and a single 1-element vector
mutate(mu = map2_dbl(probability, n, ~ (1/.y) * sum(data * .x)))
operations_df
#> # A tibble: 2 x 4
#> components probability n mu
#> <chr> <list> <dbl> <dbl>
#> 1 1 <dbl [10]> 8.93 0.504
#> 2 2 <dbl [10]> 1.07 0.506
# this doesn't work
# variance for each row, using list column, and two 1-element vectors
operations_df %>%
mutate(var = pmap_dbl(probability, n, mu, ~ (1/(..2-1)) * sum(..1 * data^2) - ..3^2))
#> Result 1 must be a single double, not NULL of length 0
# this does work
(1/(operations_df$n[1]-1)) * sum(operations_df$probability[[1]] * data^2) - operations_df$mu[1]^2
#> [1] 0.0342961
(1/(operations_df$n[2]-1)) * sum(operations_df$probability[[2]] * data^2) - operations_df$mu[2]^2
#> [1] 3.800814
# breaking it up into two map2 calls works:
operations_df %>%
mutate(var = map2_dbl(n, probability, ~ (1/(.x-1)) * sum(.y * data^2))) %>%
mutate(var = map2_dbl(var, mu, ~ .x - .y^2))
#> # A tibble: 2 x 5
#> components probability n mu var
#> <chr> <list> <dbl> <dbl> <dbl>
#> 1 1 <dbl [10]> 8.93 0.504 0.0343
#> 2 2 <dbl [10]> 1.07 0.506 3.80
【问题讨论】: