两次调用函数并每次保存不同的值

Question

我对 C 语言非常陌生，我正在编写的函数存在一些问题。任务是编写一个函数，在该函数中提示输入高度和宽度参数来绘制一个框。我编写了函数并且可以正确编译，但是我遇到的问题是我需要调用该函数两次并保存第一次调用的宽度和第二次调用的高度。现在，如果我可以使用传递引用，这将很容易，但我不允许这样做，因为函数必须是一个 int。这是我目前所拥有的。

//LaxScorupi
//11/21/2021
// C

 #include <cstdio>

int GetSize(int min, int max)
{
int range;

while (range < min || range > max)
{
    printf("Please enter a value between %d and %d: ", min, max);
    scanf("%d", &range);
}

return range;
}

/*
This is where I think I am missing something obvious. Currently, I 
have printf in place to 
just read the value back to me, but I know my "range" will be saved as 
whatever my second call
of GetSize is. I've tried creating variables for height and width, but 
am unsure how to take 
my return defined as range and store it as two different values. 
*/
 int main ()
{
int min;
int max;
int range;

range = GetSize(2, 80);
printf("Your width is %d\n", range;

range = GetSize(2, 21);
printf("Your height is %d\n", range);

return 0;
}

提前致谢 - Lax Scorupi

Answer 1

struct
{
   int height;
   int width;
}range;

range.width = GetSize(2, 80);
range.height = GetSize(2, 21);

print("Height:%d, Width:%d\n", range.height, range.width);

Answer 2

基本上，您可以将它们保存在两个不同的变量中并将它们存储在一个数组中，以便您以后使用它们。我只是将名称和数组添加到您的代码中。

#include<stdio.h>

int GetSize(int min, int max)
{
int range;

while (range < min || range > max)
{
printf("Please enter a value between %d and %d: ", min, max);
scanf("%d", &range);
}

return range;
}

int main ()
{
int min;
int max;
int range1, range2;

range1 = GetSize(2, 80);

printf("Your width is %d\n", range1);

range2 = GetSize(2, 21);
printf("Your height is %d\n", range2);

int a[2] = {range1, range2};
printf("%d %d", a[0], a[1]);

return 0;
}