Python - 用先前拆分的字符串替换给定目录中所有文件中的部分字符串

Question

我在包含一些路径的目录中有很多文件。需要浏览所有文件，并将“路径”的第一部分替换为我之前获得的其他文件。请记住，“sw”将始终是拆分后这两个部分之间的边界。

所以里面的文件路径是：

E:\p\folder\folder2\sw\first_step\step1\step2\final
E:\p\folder\folder2\sw\second_step\step1\step2\final
E:\p\folder\folder2\sw\second_step\step56\step333\final
E:\p\folder\folder2\sw\second_step\step1\step2\final
etc 

我的代码：

def findReplace(directory, find, replace, filePattern):
    for path, dirs, files in os.walk(os.path.abspath(directory)):
        for filename in fnmatch.filter(files, filePattern):         
            filepath = os.path.join(path, filename)
            with open(filepath) as f:
                s = f.read()
            s = s.replace(find, replace)
            with open(filepath, "w") as f:
                f.write(s)

base_dir = 'F:/Users/User1/Folder/'
path_to_files = '/folder1/folder2/files/'

directory = os.listdir(os.path.join(base_dir, path_to_includes_appl))

for file in directory:
    if file == None: continue
    with open (file, 'r') as f:
        content = f.read().split('\n')
        for line in content:
            if not line: continue
            # Idea here is to sepeare part we need to replace with part that has to stay
            old_path, path_to_file = line.split('sw\\')
            

findReplace(str(directory), old_path, base_dir, ".c")

最终输出应该是：

F:\Users\User1\Folder\sw\first_step\step1\step2\final
F:\Users\User1\Folder\second_step\step1\step2\final
F:\Users\User1\Folder\second_step\step56\step333\final
F:\Users\User1\Folder\second_step\step1\step2\final

注意： 请忽略“/”和“\”之间的差异

任何人都知道我做错了什么，或者对如何实现这一点有更好的想法？ 谢谢！

编辑：

这是我的新代码：

base_dir = 'F:/Users/User1/Folder/'
path_to_includes_appl =  '/folder1/folder2/files/'
# directory = os.listdir(os.path.join(base_dir, path_to_includes_appl))
directory_path = (os.path.join(base_dir, path_to_includes_appl))
directory = os.listdir(directory_path)


for file in directory:
        with open (directory_path+file, 'r') as f:
            content = f.readlines()
            for line in content:
                old_path, path_to_file = line.split('sw\\')
                findReplace(directory_path, old_path, base_dir, ".c")

当我运行它时，什么都没有发生，没有错误但也没有更新文件

Answer 1

所以我已经设法解决了这个问题，这是工作代码：

directory_path = (os.path.join(base_dir, path_to_includes_appl))
directory = os.listdir(directory_path)

for file in directory:
    with open (directory_path+file, 'r') as f:
        content = f.readlines()
    f.close()
    with open (directory_path+file, 'w') as fw:
        for line in content:
            path = pathlib.Path(line)
            index = path.parts.index('sw')
            new_path = pathlib.Path(base_dir).joinpath(*path.parts[index:])
            fw.write(str(new_path))
        fw.close()