【发布时间】:2019-01-22 15:19:50
【问题描述】:
全部,
我有来自多个表的多个左外连接。 我的 SQL 查询工作正常,如下所示:
select distinct
C.CUST_CD, C.DSC, C.BH_PHONE, A.ADDRESS, CITY.DESCR CITY, ZIP.DESCR ZIP,
CSH.UDT_DT , CSR.DSC
from
dbo.CUST C
inner join dbo.CUST_ADDR A on C.CUST_CD = A.CUST_CD and A.ADDR_CD = 5
left outer join dbo.LOCATION CITY on A.CITY_CD = CITY.LOCATION_CD
left outer join dbo.LOCATION ZIP on A.ZIP_CD = ZIP.LOCATION_CD
left outer join dbo.CUST_STS S on C.CUST_STS_CD = S.CUST_STS_CD
left outer join dbo.CUST_STS_HIS CSH on C.CUST_CD = CSH.CUST_CD
left outer join dbo.CUST_STS_REASON CSR on CSH.REASON_CD = CSR.REASON_CD
where
C.CUST_STS_CD in (5)
and CSH.CUST_STS_CD in (5)
and CSR.STS_CD in (5)
order by C.CUST_CD
我的 Lambda 表达式如下所示:
var items = (
from a in db.CUSTs
from b in db.CUST_ADDR
.Where(bb => bb.CUST_CD == a.CUST_CD && bb.ADDR_CD ==5)
from c in db.LOCATION
.Where(cc => cc.LOCATION_CD == b.CITY_CD)
.DefaultIfEmpty() // <== makes outer left join
from d in db.LOCATION
.Where(dd => dd.LOCATION_CD == c.LOCATION_CD)
.DefaultIfEmpty()
from e in db.LOCATION
.Where(ee => ee.LOCATION_CD == b.ZIP_CD)
.DefaultIfEmpty()
from f in db.CUST_STS_HIS
.Where(ff => ff.CUST_STS_CD == a.CUST_STS_CD)
.DefaultIfEmpty()
from g in db.CUST_STS_REASON
.Where(gg => gg.STS_CD == f.CUST_STS_CD)
.DefaultIfEmpty()
where (a.CUST_STS_CD == 5 && f.CUST_STS_CD == 5 && g.STS_CD == 5)
select new
{
CUSTCode = a.CUST_CD,
CUSTDesc = a.DSC,
CUSTPhone = a.BH_PHONE,
CUSTAddr = a.ADDRESS,
CUSTCity = c.DESCR,
CUSTZip = d.DESCR,
CUSTCounty = e.DESCR,
Date = f.UDT_DT,
reason = g.DSC
})
.ToList();
这是来自于 Lamda 表达式的 SQL:
SELECT
1 AS [C1],
[Filter1].[CUST_CD1] AS [CUST_CD],
[Filter1].[DSC] AS [DSC],
[Filter1].[BH_PHONE] AS [BH_PHONE],
[Filter1].[ADDRESS] AS [ADDRESS],
[Filter1].[DESCR1] AS [DESCR],
[Filter1].[DESCR2] AS [DESCR1],
[Filter1].[DESCR3] AS [DESCR2],
[Filter1].[UDT_DT] AS [UDT_DT],
[Extent7].[DSC] AS [DSC1]
FROM (SELECT [Extent1].[CUST_CD] AS [CUST_CD1], [Extent1].[DSC] AS [DSC], [Extent1].[BH_PHONE] AS [BH_PHONE], [Extent1].[ADDRESS] AS [ADDRESS], [Extent3].[DESCR] AS [DESCR1], [Extent4].[DESCR] AS [DESCR2], [Extent5].[DESCR] AS [DESCR3], [Extent6].[UDT_DT] AS [UDT_DT], [Extent6].[CUST_STS_CD] AS [CUST_STS_CD1]
FROM [DBO].[CUST] AS [Extent1]
INNER JOIN (SELECT
[CUST_ADDR].[CUST_CD] AS [CUST_CD],
[CUST_ADDR].[ADDR_CD] AS [ADDR_CD],
[CUST_ADDR].[ADDRESS] AS [ADDRESS],
[CUST_ADDR].[CITY_CD] AS [CITY_CD],
[CUST_ADDR].[ZIP_CD] AS [ZIP_CD],
[CUST_ADDR].[STATE_CD] AS [STATE_CD],
[CUST_ADDR].[ADDRESS2] AS [ADDRESS2]
FROM [DBO].[CUST_ADDR] AS [CUST_ADDR]) AS [Extent2] ON ([Extent2].[CUST_CD] = [Extent1].[CUST_CD]) AND (cast(5 as decimal(18)) = [Extent2].[ADDR_CD])
LEFT OUTER JOIN [DBO].[LOCATION] AS [Extent3] ON [Extent3].[LOCATION_CD] = [Extent2].[CITY_CD]
LEFT OUTER JOIN [DBO].[LOCATION] AS [Extent4] ON [Extent4].[LOCATION_CD] = [Extent3].[LOCATION_CD]
LEFT OUTER JOIN [DBO].[LOCATION] AS [Extent5] ON [Extent5].[LOCATION_CD] = [Extent2].[ZIP_CD]
INNER JOIN (SELECT
[CUST_STS_HIS].[CUST_CD] AS [CUST_CD],
[CUST_STS_HIS].[UDT_DT] AS [UDT_DT],
[CUST_STS_HIS].[REASON_CD] AS [REASON_CD],
[CUST_STS_HIS].[CUST_STS_CD] AS [CUST_STS_CD],
[CUST_STS_HIS].[USR_ID] AS [USR_ID],
[CUST_STS_HIS].[NOTES] AS [NOTES]
FROM [DBO].[CUST_STS_HIS] AS [CUST_STS_HIS]) AS [Extent6] ON [Extent6].[CUST_STS_CD] = [Extent1].[CUST_STS_CD]
WHERE (cast(5 as decimal(18)) = [Extent1].[CUST_STS_CD]) AND (cast(5 as decimal(18)) = [Extent6].[CUST_STS_CD]) ) AS [Filter1]
INNER JOIN (SELECT
[CUST_STS_REASON].[STS_CD] AS [STS_CD],
[CUST_STS_REASON].[REASON_CD] AS [REASON_CD],
[CUST_STS_REASON].[DSC] AS [DSC],
[CUST_STS_REASON].[RES_KEY] AS [RES_KEY]
FROM [DBO].[CUST_STS_REASON] AS [CUST_STS_REASON]) AS [Extent7] ON [Extent7].[STS_CD] = [Filter1].[CUST_STS_CD1]
我按预期获得了我的 SQL 查询结果(大约 300 条左右的记录)。但是,我的 lambda 带来了所有记录(超过 100k)。完全忽略我在声明中的“where”子句。 您能否在此查询中指出正确的方向? 感谢您的时间和考虑。
【问题讨论】:
-
A.ADDR_CD = 5 去哪儿了?
-
你可以随时查看EF生成的sql是什么,看看有什么区别。检查这个答案stackoverflow.com/questions/1412863/…
-
这是哪个 ORM - EF Core?哪个版本?
-
@GuillaumeCR - 它是这样的“来自 b”:from b in db.RET_ADDR .Where(bb => bb.RET_CD == a.RET_CD && bb.ADDR_CD == 5) .仍然带来大约 76k 条记录
-
@IvanStoev - 这来自 EF6。