【发布时间】:2021-03-08 03:28:54
【问题描述】:
我的脚本有错误,我只想显示 siswa 详细数据
错误号:1066
不是唯一的表/别名:'siswa'
选择 * FROM (
kelas,siswa) 加入siswaONsiswa.kelas_id=kelas.id其中nis= '1001'文件名:C:/xampp/htdocs/konsultasi/system/database/DB_driver.php
行号:691
我的控制器:
public function siswa_detail($id)
{
$detail = $this->m_datas->detail_data($id);
$data['detail'] = $detail;
$this->load->view('templates/header');
$this->load->view('v_bk/view_siswa_detail', $data);
$this->load->view('templates/footer');
}
我的模特:
public function detail_data($id = NULL)
{
$this->db->select('*');
$this->db->from('siswa');
$this->db->join('kelas', 'siswa.kelas_id = kelas.id');
$query = $this->db->get_where('siswa', array('nis' => $id))->row();
return $query;
}
【问题讨论】:
标签: php codeigniter codeigniter-3