【发布时间】:2014-05-06 03:36:06
【问题描述】:
我使用的是 SQL Server 2005,但我的 SQL 查询有问题。基本上,我想根据所有客户交易的最新日期获取客户所有交易的总金额,按公司分组。
样本数据:
Customer_Id Date Amount COMPANY
-------------------------------------------------
1 3/3/2014 9021 COMPANY X
2 3/3/2014 12000 COMPANY Y
2 3/15/2014 10000 COMPANY Y
2 3/30/2014 8000 COMPANY Y
4 3/13/2014 10000 COMPANY Z
5 3/14/2014 1400 COMPANY X
1 3/16/2014 2500 COMPANY X
7 3/14/2014 110 COMPANY Y
3 3/17/2014 1500 COMPANY Z
2 3/19/2014 2044 COMPANY Y
3 3/09/2014 9400 COMPANY Z
3 3/11/2014 8950 COMPANY Z
2 3/31/2014 3455 COMPANY Y
3 3/15/2014 950 COMPANY Z
6 3/15/2014 5543 COMPANY X
我想要完成的是这样的:
COMPANY TOTAL
COMPANY X 9443 --> sum from customer_id 1 (2500, as of 3/16/2014) and customer_id 6 (5542, 3/15/2014) and customer_id 5 (1400 as of 3/14/2014)
COMPANY Y 3455 --> sum from customer_id 2 (3455, as of 3/31/2014)
COMPANY Z 10950 --> sum from customer_id 4 (1000, as of 3/13/2014) and customer_id 3 (950, as of 3/15/2014)
以下是我尝试过的一些 SQL 查询,但对我的目标不起作用:
SELECT TOP (1) WITH TIES
Date, Company, SUM(Amount) AS total
FROM
tbl_Table
GROUP BY
Date, Company
ORDER BY
Date DESC
SELECT
t1.Date, t1.Company, SUM(t1.Amount) AS total
FROM
tbl_Table AS t1
INNER JOIN
(SELECT
MAX(Date) AS date, Company
FROM
tbl_Table
GROUP BY
Company) AS t2 ON t1.Date = t2.Date AND t1.Company = t2.Company
GROUP BY
t1.Date, t1.Company
WITH latest AS
(SELECT
Company, MAX(Date) AS maxdate
FROM
tbl_Table
GROUP BY
Company
)
SELECT
a.Date, a.Company, SUM(a.Amount) AS total
FROM
tbl_Table AS a
INNER JOIN
latest AS b ON a.Company = b.Company AND a.Date = b.maxdate
GROUP BY
a.Date, a.Company
【问题讨论】:
标签: sql sql-server-2005 group-by max