【问题标题】:SQL Server 2005 MAX, SUM AND GROUP BYSQL Server 2005 MAX、SUM 和 GROUP BY
【发布时间】:2014-05-06 03:36:06
【问题描述】:

我使用的是 SQL Server 2005,但我的 SQL 查询有问题。基本上,我想根据所有客户交易的最新日期获取客户所有交易的总金额,按公司分组。

样本数据:

Customer_Id    Date            Amount   COMPANY
-------------------------------------------------
1             3/3/2014          9021    COMPANY X 
2             3/3/2014          12000   COMPANY Y
2             3/15/2014         10000   COMPANY Y 
2             3/30/2014         8000    COMPANY Y 
4             3/13/2014         10000   COMPANY Z
5             3/14/2014         1400    COMPANY X 
1             3/16/2014         2500    COMPANY X 
7             3/14/2014         110     COMPANY Y 
3             3/17/2014         1500    COMPANY Z 
2             3/19/2014         2044    COMPANY Y
3             3/09/2014         9400    COMPANY Z 
3             3/11/2014         8950    COMPANY Z 
2             3/31/2014         3455    COMPANY Y 
3             3/15/2014         950     COMPANY Z 
6             3/15/2014         5543    COMPANY X

我想要完成的是这样的:

COMPANY       TOTAL
COMPANY X     9443    --> sum from customer_id 1 (2500, as of 3/16/2014) and customer_id 6 (5542, 3/15/2014) and customer_id 5 (1400 as of 3/14/2014)
COMPANY Y     3455    --> sum from customer_id 2 (3455, as of 3/31/2014)
COMPANY Z     10950   --> sum from customer_id 4 (1000, as of 3/13/2014) and customer_id 3 (950, as of 3/15/2014)

以下是我尝试过的一些 SQL 查询,但对我的目标不起作用:

SELECT TOP (1) WITH TIES 
    Date, Company, SUM(Amount) AS total
FROM         
    tbl_Table
GROUP BY 
    Date, Company
ORDER BY 
    Date DESC

SELECT     
    t1.Date, t1.Company, SUM(t1.Amount) AS total
FROM         
    tbl_Table AS t1 
INNER JOIN
    (SELECT 
        MAX(Date) AS date, Company
     FROM  
        tbl_Table
     GROUP BY 
        Company) AS t2 ON t1.Date = t2.Date AND t1.Company = t2.Company
GROUP BY 
    t1.Date, t1.Company


WITH latest AS 
(SELECT 
     Company, MAX(Date) AS maxdate
 FROM         
     tbl_Table 
 GROUP BY 
     Company
)
SELECT     
    a.Date, a.Company, SUM(a.Amount) AS total
FROM      
    tbl_Table AS a 
INNER JOIN
    latest AS b ON a.Company = b.Company AND a.Date = b.maxdate
GROUP BY 
    a.Date, a.Company

【问题讨论】:

    标签: sql sql-server-2005 group-by max


    【解决方案1】:

    根据您提供的数据,您的结果仍然不正确。

    SQLFIDDLEExample

    查询:

    SELECT t1.Company,
           SUM(t1.Amount) Total
    FROM Table1 t1
       LEFT JOIN Table1 t2
        ON t1.COMPANY = t2.COMPANY
          AND t1.Customer_Id = t2.Customer_Id
          AND t1.Date < t2.Date
       WHERE t2.Customer_Id is null
    GROUP BY t1.Company
    

    结果:

    |   COMPANY | TOTAL |
    |-----------|-------|
    | COMPANY X |  9443 |
    | COMPANY Y |  3565 |
    | COMPANY Z | 11500 |
    

    【讨论】:

    • 谢谢,@贾斯汀。你的解决方案解决了这一切。虽然我现在不理解你的 sql 代码(我是 sql 查询的新手),但我很快就会。再次感谢。关于“根据您提供的数据,您的结果仍然不正确。”,我忽略了这一点。对不起。
    【解决方案2】:

    试试这个

        WITH cte AS (
             SELECT Amount,Company,
                    ROW_NUMBER() OVER (PARTITION BY Customer_Id ORDER BY CAST([Date] AS DATETIME) desc )   
                    AS dateRowRank
        )
    
       SELECT Company,SUM(Amount)
       FROM cte
       WHERE dateRowRank=1
       GROUP BY Company
    

    【讨论】:

    • 哈桑爵士。我不知道您的 sql 代码有什么问题,但是当我执行查询时,我的 sql server 2005 崩溃了。我注意到这个问题也发生在我尝试过的其他 sql 查询中,其中包含“row_number()”和“over partition”。
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