MySQL - 分组的每列的 SUM 总值答案

【问题标题】：MySQL - SUM total values for each column groupedMySQL - 分组的每列的 SUM 总值
【发布时间】：2021-01-07 15:57:27
【问题描述】：

我有一个查询，它返回按月份分组的记录，并根据条件计算表上记录的总和：

SELECT USERS.ID AS ID, PROPERTIES.PROP_TYPE AS TIPO
,SUM(IF(MONTH(PROPERTIES.created_at) = 1, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as ENE
,SUM(IF(month(PROPERTIES.created_at) = 2, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS FEB
,SUM(IF(month(PROPERTIES.created_at) = 3, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as MAR
,SUM(IF(month(PROPERTIES.created_at) = 4, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS ABR
,SUM(IF(month(PROPERTIES.created_at) = 5, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS MAY
,SUM(IF(month(PROPERTIES.created_at) = 6, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUN
,SUM(IF(month(PROPERTIES.created_at) = 7, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUL
,SUM(IF(month(PROPERTIES.created_at) = 8, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS AGO
,SUM(IF(month(PROPERTIES.created_at) = 9, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as SEP
,SUM(IF(month(PROPERTIES.created_at) = 10, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as OCT
,SUM(IF(month(PROPERTIES.created_at) = 11, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as NOV
,SUM(IF(month(PROPERTIES.created_at) = 12, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as DIC
FROM PROPERTIES
LEFT JOIN USERS ON PROPERTIES.PROP_CAPPER_EMAIL = USERS.EMAIL_LOCAL_CRM
WHERE   USERS.ID = 1283
GROUP BY PROPERTIES.PROP_TYPE, USERS.ID

这个查询的输出是：

我还需要对每个月的所有值进行求和，并在最后一行显示该结果，预期输出为：

如何调整我的查询以获取包含列 vales SUM 的最后一行？

问候！

【问题讨论】：

标签： mysql sql group-by sum rollup

【解决方案1】：

最简单的方法是使用with rollup：

 GROUP BY PROPERTIES.PROP_TYPE, USERS.ID WITH ROLLUP

不过，这会为每个子组提供单独的行。

或者，您可以使用 CTE：

with t as (
      <your query here>
     )
select t.*
from t
union all
select null, null, sum(ene), sum(feb), . . .
from t;

【讨论】：

谢谢@Gordo Linioff .. ROLLUP 的问题是所有值都正确求和，但它为所有分组的“TIPO”列创建了一个新行，我只需要为所有 SUM 增加一行

【解决方案2】：

有人用 UNION 方法给我发了评论，评论被删除了，但我读了。

所以，我认为解决方案是将其添加到查询中：

UNION
SELECT USERS.ID AS ID, 'Total' AS TIPO
    ,SUM(IF(MONTH(PROPERTIES.created_at) = 1, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as ENE
    ,SUM(IF(month(PROPERTIES.created_at) = 2, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS FEB
    ,SUM(IF(month(PROPERTIES.created_at) = 3, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as MAR
    ,SUM(IF(month(PROPERTIES.created_at) = 4, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS ABR
    ,SUM(IF(month(PROPERTIES.created_at) = 5, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS MAY
    ,SUM(IF(month(PROPERTIES.created_at) = 6, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUN
    ,SUM(IF(month(PROPERTIES.created_at) = 7, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUL
    ,SUM(IF(month(PROPERTIES.created_at) = 8, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS AGO
    ,SUM(IF(month(PROPERTIES.created_at) = 9, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as SEP
    ,SUM(IF(month(PROPERTIES.created_at) = 10, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as OCT
    ,SUM(IF(month(PROPERTIES.created_at) = 11, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as NOV
    ,SUM(IF(month(PROPERTIES.created_at) = 12, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as DIC
FROM PROPERTIES
LEFT JOIN USERS ON PROPERTIES.PROP_CAPPER_EMAIL = USERS.EMAIL_LOCAL_CRM
WHERE   USERS.ID = 755
GROUP BY USERS.ID

通过那个 UNION，我使用来自原始帖子的不同行数据来获得这个结果：

所以最终查询将是：

SELECT USERS.ID AS ID, PROPERTIES.PROP_TYPE AS TIPO
,SUM(IF(MONTH(PROPERTIES.created_at) = 1, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as ENE
,SUM(IF(month(PROPERTIES.created_at) = 2, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS FEB
,SUM(IF(month(PROPERTIES.created_at) = 3, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as MAR
,SUM(IF(month(PROPERTIES.created_at) = 4, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS ABR
,SUM(IF(month(PROPERTIES.created_at) = 5, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS MAY
,SUM(IF(month(PROPERTIES.created_at) = 6, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUN
,SUM(IF(month(PROPERTIES.created_at) = 7, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUL
,SUM(IF(month(PROPERTIES.created_at) = 8, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS AGO
,SUM(IF(month(PROPERTIES.created_at) = 9, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as SEP
,SUM(IF(month(PROPERTIES.created_at) = 10, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as OCT
,SUM(IF(month(PROPERTIES.created_at) = 11, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as NOV
,SUM(IF(month(PROPERTIES.created_at) = 12, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as DIC
FROM PROPERTIES
LEFT JOIN USERS ON PROPERTIES.PROP_CAPPER_EMAIL = USERS.EMAIL_LOCAL_CRM
WHERE   USERS.ID = 755
GROUP BY PROPERTIES.PROP_TYPE, USERS.ID
UNION
SELECT USERS.ID AS ID, 'Total'
,SUM(IF(MONTH(PROPERTIES.created_at) = 1, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as ENE
,SUM(IF(month(PROPERTIES.created_at) = 2, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS FEB
,SUM(IF(month(PROPERTIES.created_at) = 3, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as MAR
,SUM(IF(month(PROPERTIES.created_at) = 4, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS ABR
,SUM(IF(month(PROPERTIES.created_at) = 5, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS MAY
,SUM(IF(month(PROPERTIES.created_at) = 6, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUN
,SUM(IF(month(PROPERTIES.created_at) = 7, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as JUL
,SUM(IF(month(PROPERTIES.created_at) = 8, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) AS AGO
,SUM(IF(month(PROPERTIES.created_at) = 9, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as SEP
,SUM(IF(month(PROPERTIES.created_at) = 10, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as OCT
,SUM(IF(month(PROPERTIES.created_at) = 11, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as NOV
,SUM(IF(month(PROPERTIES.created_at) = 12, PROPERTIES.PROP_EXCLUSIVE = 'Exclusiva',0)) as DIC
FROM PROPERTIES
LEFT JOIN USERS ON PROPERTIES.PROP_CAPPER_EMAIL = USERS.EMAIL_LOCAL_CRM
WHERE   USERS.ID = 755
GROUP BY USERS.ID

【讨论】：