按年龄范围划分的 SQL 组

Question

SQL 2005, 我有一个包含“ages_c”列的表，我需要按年龄范围对记录进行分组。 这是我在这个网站上找到的查询，它让我 90% 在那里，但“分组依据”出错，*无效的列名 'age_range'*

 select 
  case
   when age_c <18 then 'Under 18'
   when age_c between 18 and 24 then '18-24'
   when age_c between 25 and 34then '25-34'
 END as age_range, 
 Count(*) as count
 from contacts
 group by age_range
 order by age_range

当我按“age_c”分组和排序时，我的结果是：

  Under 18  1
  18-24 1
  18-24 1
  25-34 1

我想要的是：

 Under 18   1
  18-24 2      
  25-34 1

谢谢。

Answer 1

CASE WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 20 AND 29 THEN '20-29'

        WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 30 AND 39 THEN '30-39'

        WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 40 AND 49 THEN '40-49'

           WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 50 AND 59 THEN '50-59'


        ELSE '60 AND Older'

    END AS age_group_Frequency,

count (CASE WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 20 AND 29 THEN '20-29'

        WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 30 AND 39 THEN '30-39'

        WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 40 AND 49 THEN '40-49'

           WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 50 AND 59 THEN '50-59'


        ELSE '60 AND Older'

    END) AS age_group
       
     


  FROM

put your statement****

where

*****

  group by 
CASE WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 20 AND 29 THEN '20-29'

        WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 30 AND 39 THEN '30-39'

        WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 40 AND 49 THEN '40-49'

           WHEN DATEDIFF(YEAR, DateOfBirth, GETDATE()) BETWEEN 50 AND 59 THEN '50-59'


        ELSE '60 AND Older'

    END

Answer 2

如果您的数据库支持 FILTER WHERE 语法，那么这可以以非常优雅的方式归档：

SELECT COUNT(id) FILTER (WHERE (age < 18)) AS "Under 18",
       COUNT(id) FILTER (WHERE (age >= 18 AND age <= 24)) AS "18-24",
       COUNT(id) FILTER (WHERE (age >= 25 AND age <= 34)) AS "25-34"
FROM contacts

如果没有，或者这个：

SELECT count(CASE WHEN (age < 18) THEN id ELSE null END)                AS "Under_18",
       count(CASE WHEN (age >= 18 AND age <= 24) THEN id ELSE null END) AS "18-24",
       count(CASE WHEN (age >= 25 AND age <= 34) THEN id ELSE null END) AS "25-34"
FROM contacts

Answer 3

试试这个方法：

 SELECT SUM(CASE WHEN age_c < 18 THEN 1 ELSE 0 END) AS [Under 18],
        SUM(CASE WHEN age_c BETWEEN 18 AND 24 THEN 1 ELSE 0 END) AS [18-24],
        SUM(CASE WHEN age_c BETWEEN 25 AND 34 THEN 1 ELSE 0 END) AS [25-34]
 FROM contacts

Answer 4

您不能按在查询中创建的列进行分组。你必须这样做：

SELECT count(*), * FROM 
(
select 
  case
   when age_c <18 then 'Under 18'
   when age_c between 18 and 24 then '18-24'
   when age_c between 25 and 34then '25-34'
 END as age_range 
 from contacts
) t
group by age_range
order by age_range

或分组方式

case
       when age_c <18 then 'Under 18'
       when age_c between 18 and 24 then '18-24'
       when age_c between 25 and 34then '25-34'
END

Answer 5

这是您使用的实际代码吗？它看起来不像，因为您在 34 和 then 之间缺少一个空格。该代码会在 SQL 中出错。介意分享实际未修改的查询吗？

无论如何，您可以使用临时表或嵌套查询。

SELECT
 CASE
  WHEN age_c <18 THEN 'Under 18'
  WHEN age_c BETWEEN 18 AND 24 THEN '18-24'
  WHEN age_c BETWEEN 25 AND 34 THEN '25-34'
END AS age_range, 
INTO #TempAges
FROM contacts
ORDER BY age_c

SELECT COUNT(*) FROM #TempAges GROUP BY age_range

完成后不要忘记删除临时表

Answer 6

按age_c 分组——age_range 不是物理列。更具体地说，这样做：

group by case
   when age_c <18 then 'Under 18'
   when age_c between 18 and 24 then '18-24'
   when age_c between 25 and 34then '25-34'
 END

由于age_range 是一个别名列，group by 根本不知道它。分组发生在计算列集之前。您可以在其中使用别名的唯一子句是order by，因为这是在计算列集之后执行的唯一子句。