【发布时间】:2017-05-29 08:32:43
【问题描述】:
编辑:我已经发布了a new question(而不是编辑),因为我尝试过的内容和代码非常冗长,意味着完全替换了这个问题。
我正在使用 PDO 处理INSERT将多行写入 SQLite 表,但使用绑定参数执行查询时遇到问题。我有三个带有架构的表:
列 schoolB_equivalencies:
- equivalency_id 整数主键自动增量
- schoolA_id INTEGER NOT NULL
- schoolB_id INTEGER NOT NULL
- is_archived INTEGER NOT NULL
- 外键 (schoolA_id) 参考 schoolA_courses (id)
- 外键 (schoolB_id) REFERENCES schoolB_courses (id)
schoolA_courses 的列:
- schoolA_courses id INTEGER PRIMARY KEY AUTOINCREMENT
- 课程前缀文本
- course_number 整数
- ...其他字段
schoolB_courses 的列:
- schoolB_courses id INTEGER PRIMARY KEY AUTOINCREMENT
- 课程前缀文本
- course_number 整数
- ...其他字段
我正在尝试使用prepare()、一个值数组和一个子查询一次进行多个插入。运行INSERT 语句一次有效(插入一行):
$dir = 'sqlite:/path/to/courses.sqlite3';
$dbh = new PDO($dir) or die("error");
$stmt = $dbh->prepare('INSERT INTO schoolB_equivalencies (schoolA_id, schoolB_id, is_archived) VALUES ( (SELECT id from schoolA_courses WHERE course_number="103" AND course_prefix="RPED"), (SELECT id from schoolB_courses WHERE course_number="251" AND course_prefix="ARCH"),0)');
$stmt->execute();
但是,当我使用绑定参数和值数组合并相同的语句时,不会插入任何行:
$dir = 'sqlite:/path/to/courses.sqlite3';
$dbh = new PDO($dir) or die("error");
$selections = array(
0 => array(
0 => "RPED", // THE schoolA COURSE PREFIX
1 => "103", //THE schoolA COURSE NUMBER
2 => "ARCH", //THE schoolB COURSE PREFIX
3 => "251" //THE schoolB COURSE NUMBER
),
1 => array(
0 => "RPED", // THE schoolA COURSE PREFIX
1 => "126", //THE schoolA COURSE NUMBER
2 => "ARCH", //THE schoolB COURSE PREFIX
3 => "261" //THE schoolB COURSE NUMBER
)
);
$stmt = $dbh->prepare('INSERT INTO schoolB_equivalencies (schoolA_id, schoolB_id, is_archived) VALUES ( (SELECT id from schoolA_courses WHERE course_number=:schoolA_code AND course_prefix=:schoolA_prefix), (SELECT id from schoolB_courses WHERE course_number=:schoolB_code AND course_prefix=:schoolB_prefix),0)');
foreach ( $selections as $selection ):
$stmt->bindParam(':schoolA_number', $selection[1]);
$stmt->bindParam(':schoolA_prefix', $selection[0]);
$stmt->bindParam(':schoolB_number', $selection[3]);
$stmt->bindParam(':schoolB_prefix', $selection[2]);
$stmt->execute();
print_r($dbh->errorInfo());
endforeach;
error_info() 的输出在两次插入上都显示代码 0000,这似乎是一个“成功”指示器,但没有插入任何行。基于单个INSERT 有效并且error_info() 报告成功的事实,我猜我绑定参数的方式有问题。
【问题讨论】:
-
你在循环中执行了两次查询
-
我已将
$stmt->execute();移到循环之外,但该语句仍然没有INSERT任何行。 -
将查询语句移到foreach循环内
标签: php sql pdo sqlite prepared-statement