在oracle sql中根据周末和工作日分离信息

Question

我想得到以下输出

enrollment_month	weekend_revenue	weekday_revenue
jun	550	790
may	1570	2020

这是我的代码：

select g.enrollment_month, sum(g.total_revenue) as weekday_revenue 
from gracieMusicFact g
where g.lesson_day in ('Monday','Tuesday','Wednesday','Thursday','Friday')
group by enrollment_month;

select g.enrollment_month, sum(g.total_revenue) as weekend_revenue 
from gracieMusicFact g
where g.lesson_day in ('Saturday','Sunday')
group by enrollment_month;

Union 只给我一个weekday_revenue 或weekday_revenue。如何使用不同的条件创建两个不同的选择语句？

谢谢

编辑：使用 union all 给我这个输出：

| enrollment_month   | weekday_revenue |

| jun|  790 |
| may| 2020 |
| jun|  550 |
| may| 1570 |

Answer 1

使用条件聚合：

select g.enrollment_month,
       sum(case when g.lesson_day in ('Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday') then g.total_revenue else 0 end) as weekday_revenue,
       sum(case when g.lesson_day in ('Saturday', 'Sunday') then g.total_revenue else 0 end) as weekend_revenue
from gracieMusicFact g
group by enrollment_month;

Answer 2

我认为您需要使用 UNION ALL

Union 和 Union All 唯一的区别是 Union All 不会删除重复的行或记录，而是从所有表中选择满足您的具体查询条件的所有行并将它们组合到结果表中. ... 而 UNION ALL 可用于所有数据类型列。

What is the difference between UNION and UNION ALL?