读取文本文件并提取 php 中的一些元素

Question

我有一个文本文件。我想读取文件并从元素中获取一些数据。当我阅读此文件时，它可能是返回字符串（我不确定）。该文件包含一些数据，例如以下内容：

Can we get Prism Cluster Mail in summarize way like below. 

----------------------------------------------------------------

{
"Employees" : [
{
"userId":"rirani",
"jobTitleName":"Developer",
"firstName":"Romin",
"lastName":"Irani",
"preferredFullName":"Romin Irani",
"employeeCode":"E1",
"region":"CA",
"phoneNumber":"408-1234567",
"emailAddress":"romin.k.irani@gmail.com"
},
{
"userId":"nirani",
"jobTitleName":"Developer",
"firstName":"Neil",
"lastName":"Irani",
"preferredFullName":"Neil Irani",
"employeeCode":"E2",
"region":"CA",
"phoneNumber":"408-1111111",
"emailAddress":"neilrirani@gmail.com"
},
{
"userId":"thanks",
"jobTitleName":"Program Directory",
"firstName":"Tom",
"lastName":"Hanks",
"preferredFullName":"Tom Hanks",
"employeeCode":"E3",
"region":"CA",
"phoneNumber":"408-2222222",
"emailAddress":"tomhanks@gmail.com"
}
]
}

我想提取 userId、jobTitleName 和 phoneNumber。我怎样才能做到这一点？我是 php 的新手。我试过以下代码。但它不能正常工作。有人可以帮忙吗？

header('Content-type: application/json');   
    $data = preg_split("/\r\n/", file_get_contents("cluster.txt")); 
    $dt= json_encode($data, JSON_UNESCAPED_SLASHES);
    $final_dt=stripslashes($dt);
    $final_dt_arr=json_decode($final_dt,true);
    //echo "<pre>"; print_r($final_dt_arr);
    echo $final_dt;

Answer 1

我看一下你上面的脚本，你已经使用了json_decode，这是一个好的开始。 你能试试下面的代码（我的大部分项目）使用它吗：

// Read the JSON file into a string
$json_string = file_get_contents('urjsonfile.json');

// Decode the JSON string into a PHP object
$data = json_decode($json_string);

// Extract the desired data from the object
foreach ($data->Employees as $employee) {
    $userId = $employee->userId;
    $jobTitleName = $employee->jobTitleName;
    $phoneNumber = $employee->phoneNumber;

    // Do something with the extracted data, such as print it out
    echo "User ID: $userId, Job Title: $jobTitleName, Phone Number: $phoneNumber
";
}

1. file_get_contents()函数将JSON文件读入字符串
2. 使用json_decode()解码为PHP对象
3. foreach 循环然后遍历雇员对象中的数组，提取所需的数据。

   您还可以将第二个参数作为 true 传递，以返回关联数组。

Answer 2

据我了解你的问题。我分享了我的答案。希望它可能有所帮助。

PHP

header('Content-type: application/json');   
// $data = preg_split("/
/", file_get_contents("cluster.txt")); 
$data = file_get_contents("cluster.txt"); 
$_arrdata = json_decode($data, true);

$result_array = [];
foreach( $_arrdata['Employees'] as $key=>$cluster ){
  $result_array[$key]['userId'] = $cluster['userId'];
  $result_array[$key]['jobTitleName'] = $cluster['jobTitleName'];
  $result_array[$key]['phoneNumber'] = $cluster['phoneNumber'];
}

print_r($result_array);

输出将如下所示。

Array
(
    [0] => Array
        (
            [userId] => rirani
            [jobTitleName] => Developer
            [phoneNumber] => 408-1234567
        )

    [1] => Array
        (
            [userId] => nirani
            [jobTitleName] => Developer
            [phoneNumber] => 408-1111111
        )

    [2] => Array
        (
            [userId] => thanks
            [jobTitleName] => Program Directory
            [phoneNumber] => 408-2222222
        )

)