基于共同值按值、字母和频率分组和排序

Question

所以我正在与 MS Access 合作，并让这个参与者列表包含三列年龄、名称和年龄组，并希望它首先按名称排序，然后按年龄排序，还按基于相同名称的年龄组的频率排序。例如：

age | age_group |name  
----------------------
1      0-1        Jeff
10     10=<       Dave
10     10=<       Dave
5      5-7        Carl
2      2-4        Sam
3      2-4        Carl
4      2-4        Sam
2      2-4        Sam
5      5-7        Carl
6      5-7        Jeff
7      5-7        Dave
10     10=<       Jeff
8      8-9        Jeff

所以它首先看起来像这样，按名称和年龄排序

----------------------
10     10=<       Jeff
8      8-9        Jeff
6      5-7        Jeff
1      0-1        Jeff
10     10=<       Dave
10     10=<       Dave
7      5-7        Dave
5      5-7        Carl
5      5-7        Carl
3      2-4        Carl
4      2-4        Sam
2      2-4        Sam
2      2-4        Sam

最后按age_group 频率降序排列 10=

age | age_group |name  
----------------------
10     10=<       Dave
10     10=<       Dave
7      5-7        Dave
10     10=<       Jeff
8      8-9        Jeff
6      5-7        Jeff
1      0-1        Jeff
5      5-7        Carl
5      5-7        Carl
3      2-4        Carl
4      2-4        Sam
2      2-4        Sam
2      2-4        Sam

这可以在 SQL 或 VBA 中执行吗？我得到了第一个与之合作的人：

SELECT participants.name, participants.age_group, participants.age, *
FROM participants
ORDER BY participants.name, participants.age DESC;

但是我在执行第二步时完全迷失了...... 如果您能帮助我，将不胜感激。

Answer 1

试试这个：

select p1.name, p2.age_group, p2.age
from participants as p1
left join (select name, age_group, count(1) as freq from participants group by name, age_group) as p2
on p1.name= p2.name and p1.age_group = p2.age_group
order by name,age, p2.freq desc

访问：

select p1.name, p1.age_group, p1.age
from participants as p1
left join 

(select name, age_group, count(1) as freq 
from participants group by name, age_group) as p2

on p1.name= p2.name and p1.age_group = p2.age_group
order by p1.name, p1.age, p2.freq desc

访问输出：

Answer 2

这个花哨的 SQL 将提供分组输出：

SELECT 
    T3.age, T3.age_group, T3.name
FROM 
    Participants As T3
INNER JOIN

    (SELECT [age] * 1000 + Count(*) AS rating, T.name
    FROM participants AS T 
    INNER JOIN 

        (SELECT Max(participants.age) AS maxage, participants.name
        FROM participants
        GROUP BY participants.name) AS T2 

    ON (T.age = T2.maxage) AND (T.name = T2.name)
    GROUP BY T.name, T.age
    ORDER BY [age] * 1000 + Count(*) DESC) AS T4

ON T3.name = T4.name
ORDER BY T4.rating Desc, T3.age Desc

输出：