为什么我得到输出 <map object at 0x00000...> 和 <filter object at 0x00000....>

Question

import sys

#Multiply the value in the list based on the selected value of s
def scale(l, s):
    return map(lambda x: x * s, l)

#Sort the value based on the last digit value
def sort(l):
    return sorted(l, key=lambda x: x % 10)

#Output number if is greater than average total
def goodSales(l):
    return filter(lambda x: x > sum(l) / len(l), l)


seq = sys.argv[1]
sca = sys.argv[2]

seq = [int(x) for x in seq.split(',')]
sca = int(sca)


print('The scaled number is:', scale(seq, sca),
      'The sorted sales numbers are:', sort(seq),
      'The good sales numbers are:', goodSales(seq),)

因此，当我尝试运行该程序时，我将面临输出将显示 <map object at 0x00000...> 和 <filter object at 0x00000....> 的问题。我不太确定出了什么问题，任何人都可以提供一些建议。

输入

python sales.py 10,20,30,40,50,60 2

预期产出

The scaled number is: [20, 40, 60, 80, 100, 120] The sorted sales
numbers are: [10, 20, 30, 40, 50, 60] The good sales numbers are:
[40, 50, 60]

Answer 1

像这样改变你的功能，

#Multiply the value in the list based on the selected value of s
def scale(l, s):
    return list(map(lambda x: x * s, l))

#Output number if is greater than average total
def goodSales(l):
    return list(filter(lambda x: x > sum(l) / len(l), l))

map 返回地图对象，filter 返回过滤器对象，因此将它们转换为列表。

Answer 2

您可以使用 List Comprehensions，它更简洁，例如：

items = [
    ("name", 13),
    ("age", 12)

]

prices = [item[1] for item in items]
print(prices)