我希望你的问题是正确的。
我输入了一些可能与您的描述相符的示例数据:日期和金额。为简单起见,每个月一行。您可以从日期中提取季度,并将其保留为附加列,然后按该列过滤。
WITH
-- some sample data: date and amount ...
indata(dt,amount) AS (
SELECT DATE '2020-01-15', 234.45
UNION ALL SELECT DATE '2020-02-15', 344.45
UNION ALL SELECT DATE '2020-03-15', 345.45
UNION ALL SELECT DATE '2020-04-15', 346.45
UNION ALL SELECT DATE '2020-05-15', 347.45
UNION ALL SELECT DATE '2020-06-15', 348.45
UNION ALL SELECT DATE '2020-07-15', 349.45
UNION ALL SELECT DATE '2020-08-15', 350.45
UNION ALL SELECT DATE '2020-09-15', 351.45
UNION ALL SELECT DATE '2020-10-15', 352.45
UNION ALL SELECT DATE '2020-11-15', 353.45
UNION ALL SELECT DATE '2020-12-15', 354.45
)
-- real query starts here ...
SELECT
EXTRACT(QUARTER FROM dt) AS the_quarter
, CAST(
TIMESTAMPADD(
QUARTER
, CAST(EXTRACT(QUARTER FROM dt) AS INTEGER)-1
, TRUNC(dt,'YEAR')
)
AS DATE
) AS qtr_start
, *
FROM indata;
-- out the_quarter | qtr_start | dt | amount
-- out -------------+------------+------------+--------
-- out 1 | 2020-01-01 | 2020-01-15 | 234.45
-- out 1 | 2020-01-01 | 2020-02-15 | 344.45
-- out 1 | 2020-01-01 | 2020-03-15 | 345.45
-- out 2 | 2020-04-01 | 2020-04-15 | 346.45
-- out 2 | 2020-04-01 | 2020-05-15 | 347.45
-- out 2 | 2020-04-01 | 2020-06-15 | 348.45
-- out 3 | 2020-07-01 | 2020-07-15 | 349.45
-- out 3 | 2020-07-01 | 2020-08-15 | 350.45
-- out 3 | 2020-07-01 | 2020-09-15 | 351.45
-- out 4 | 2020-10-01 | 2020-10-15 | 352.45
-- out 4 | 2020-10-01 | 2020-11-15 | 353.45
-- out 4 | 2020-10-01 | 2020-12-15 | 354.45
如果您按季度过滤,您可以按该列对数据进行分组...