如何显示来自另一个子查询的日期范围和引用？

Question

我有一个活动表列表..现在我想获取每天创建的活动计数

例如。结果是：

Date          Count
01/10/2016    100
02/10/2016    20
03/10/2016    3000

从网上搜索了几个小时，这是工作代码：

DECLARE @start_date DATE = '2016-10-01';
DECLARE @end_date DATE= '2016-10-10';

WITH    AllDays
        AS ( SELECT   @start_date AS [Date]
               UNION ALL
              SELECT   DATEADD(DAY, 1, [Date])
            FROM     AllDays
               WHERE    [Date] < @end_date ),
       PartitionCount
       AS (select count(*)      AS [Count]
          from Activities act
          where CAST(act.CreatedDate AS DATE) = '2016-10-01')
SELECT distinct [AllDays].[Date], [PartitionCount].[Count]
FROM   AllDays, PartitionCount, Activities
ORDER BY [AllDays].[Date]
OPTION (MAXRECURSION 0)

这将给出以下结果：

Date          Count
01/10/2016    100
02/10/2016    100
03/10/2016    100

然而，这个只得到当天2016-10-01的计数。

所以我尝试更改这部分代码，以便活动创建日期等于 AllDays 的日期列，并获取该特定日期的活动计数。

AS (select count(*)     AS [Count]
from Activities act
where CAST(act.CreatedDate AS DATE) = [AllDays].[Date])

但是，这会报错

“无法绑定多部分标识符”

非常感谢您对我如何进行此操作并获得所需结果的帮助：

Date          Count
01/10/2016    100
02/10/2016    20
03/10/2016    3000

示例表如下所示

Table: Activities

ID Title        CreatedDate         
1 Activity1 2016-10-03 10:00:00.000
2 Activity2 2016-10-03 11:30:00.000
3 Activity3 2016-10-03 14:00:00.000
4 Activity4 2016-10-03 14:30:00.000
5 Activity5 2016-10-04 10:00:00.000
6 Activity6 2016-10-05 11:00:00.000
7 Activity7 2016-10-06 10:00:00.000
8 Activity8 2016-10-07 11:00:00.000

Answer 1

试试这个简单的例子， 创建过程并传递 2 个参数 StartDate、EndDate 和 Execute SP。

  declare @StartDate Date ='2016-10-01';
    declare @EndDate Date ='2016-10-10';

    select CreatedDate,COUNT(*) Count from Activities 
    where Convert(Date,CreatedDate) between @StartDate and @EndDate
    Group by CreatedDate 

Answer 2

根据我的理解，您希望 Count 用于每一天的行。为此，您可以在给定范围内的每一天执行Group By，然后还可以执行COUNT 以获得您想要的内容，如下所示，

SELECT DATEADD(DAY,0, datediff(day,0, date)) As Date, COUNT(*) As Cont 
FROM #temp
WHERE date BETWEEN @startDate AND @endDate
GROUP By DATEADD(DAY,0, DATEDIFF(DAY,0, date))