基于对象的Const数组保证对象的穷举性和正确性答案

【问题标题】：Ensure Exhaustiveness and Correctness of Object based on Const Array of Objects基于对象的Const数组保证对象的穷举性和正确性
【发布时间】：2023-02-02 23:44:34
【问题描述】：

鉴于以下ROUTES：

const ROUTES = [
  { name: "Login", path: "/login", id: "login" },
  { name: "Registration", path: "/registration", id: "registration" },
  { name: "Settings", path: "/settings", id: "settings" },
] as const;

我如何创建一个类型 (SomeType) 用于：

每个id都被用作键
每个path都被用作一个值

给定ROUTES 配置，所有键 (id) 都与其值 (path) 一对一匹配

例如：

# correct
const correctIdToPaths: SomeType = {
  login: "/login",
  registration: "/registration",
  settings: "/settings", 
} as const

# wrong
const duplicatedValues: SomeType = {
  login: "/registration", # error, id "login" does not match path "/registration"
  registration: "/registration",
  settings: "/settings", 
} as const

# wrong
const missingKey: SomeType = {
  login: "/login",
  registration: "/registration",
} as const # error: "settings" is missing

【问题讨论】：

标签： typescript

【解决方案1】：

您可以使用 typeof ROUTES[number] 获取数组中 Routes 的并集，并创建一个映射类型，您将 remap the key 映射到 id：

type SomeType = {[Route in typeof ROUTES[number] as Route['id']]: Route['path']}
// type SomeType = {login: "/login", registration: "/registration", settings: "/settings"}

TypeScript playground

【讨论】：