显示上一年的总和答案

【问题标题】：Display sum from previous year显示上一年的总和
【发布时间】：2016-07-28 23:22:34
【问题描述】：

我有如下选择语句：

  select [Fiscal Year], sum([value]), 
         YEAR(DATEADD(year,-1,[Fiscal Year])) as previous_year
  from [table1] 
  group by [Fiscal Year]

如何在上一年的previous_year、sum([value])之后添加？

【问题讨论】：

LAG/LEAD 如果 SQL Server 2012+，如果较低则自加入
@4est 很高兴为您提供帮助！

标签： sql sql-server sql-server-2008 datetime sqldatetime

【解决方案1】：

--to prepare the environment, let said this is your table
declare @table table
(
  fiscalYr integer,
  Value integer,
  previousyr integer,
  prevValue integer
)

--to prepare the value, let said these are your value
insert into @table values (2014,165,2013,0);
insert into @table values (2015,179,2014,0);
insert into @table values (2016,143,2015,0);

--the SQL
select A.fiscalYr,A.Value,A.previousyr, B.Value
from @table A left join
@table B on B.fiscalYr = A.previousyr

这就是我得到的答案

财政年度|价值|上一页|价值

2014| 165| 2013|空

2015| 179| 2014| 165

2016| 143| 2015| 179

【讨论】：

【解决方案2】：

请尝试以下 SQL 2008 查询

select t1.[Fiscal Year],t1.Value,(t1.[Fiscal Year]-1) [previous_year],t2.Value [previous_value]
from  
(  select [Fiscal Year], sum([value]) value
  from [table1] 
  group by [Fiscal Year] 
)t1
LEFT JOIN
(  
select [Fiscal Year], sum([value]) value
  from [table1] 
  group by [Fiscal Year] 
)t2
ON t1.[Fiscal Year]=t2.[Fiscal Year]+1

SQL demo link

【讨论】：

【解决方案3】：

如果您使用的是 SQL Server 2012+，则可以使用 LAG 获取上一行的值：

;with cte as (
  select [Fiscal Year], sum([value]) AS value, 
  from [table1] 
  group by [Fiscal Year]
)
select [Fiscal Year], value, 
       [Fiscal Year] - 1, lag(value) over (order by [Fiscal Year]) as prev_value
from cte

【讨论】：

这是 SQL Server 2008 :/，这是另一种方法吗？