使用列表生成表子集答案

【问题标题】：Generate a table subset with a list使用列表生成表子集
【发布时间】：2023-01-31 06:22:30
【问题描述】：

我在表中有一组主题，我想删除一个子集（例如，主题 1 和主题 2）。有没有办法使用列表获取子集？或者我是否需要有一个可以用来选择子集的属性？

subject.Subject()

# *subject      sex    
# +----------+ +-----+
# subject1     F      
# subject2     M      
# subject3     M      
# subject4     M      

(subject.Subject & "subject=subject1").delete() # Delete individually 1
(subject.Subject & "subject=subject2").delete() # Delete individually 2

(subject.Subject & "sex='M'").delete() # Delete by attribute

(subject.Subject & "subject IN ('subject1','subject2')").delete() # pseudocode, by list

for s in ['1', '2']: # not ideal
    (subject.Subject & f'subject=\"subject{s}\"').delete(safemode=False)

【问题讨论】：

标签： datajoint

【解决方案1】：

我现在认为以下是最有效的：

(subject.Subject & "subject in ('subject1', 'subject2')").delete()

【讨论】：