如何从对象数组中返回重复元素

Question

data= [
  { "id": 0, "name": "name1", "age": 12, "city": "cityA" },
  { "id": 1, "name": "name2", "age": 7, "city": "cityC" },
  { "id": 2, "name": "name3", "age": 23, "city": "cityB" },
  { "id": 2, "name": "name1", "age": 12, "city": "cityA" }
];

我如何退回具有相同名称和年龄的物品？

我正在尝试这样的事情，但它返回数组中的每个元素

data.some(d => {
for (const it of form) {
if (it.name == d.name && it.age == d.age) {
arr.push(it)....

Answer 1

您必须确保您没有与同一项目进行比较，其中属性始终匹配：

data= [
  { "id": 0, "name": "name1", "age": 12, "city": "cityA" },
  { "id": 1, "name": "name2", "age": 7, "city": "cityC" },
  { "id": 2, "name": "name3", "age": 23, "city": "cityB" },
  { "id": 2, "name": "name1", "age": 12, "city": "cityA" }
];

const res = data.filter(item => data.some(i => i !== item && item.name === i.name && item.age === i.age))
console.log(res)