用两位数和四位数年份投射 TO_DATE 列答案

【问题标题】：Cast column TO_DATE with two and four digit years用两位数和四位数年份投射 TO_DATE 列
【发布时间】：2023-01-24 00:54:55
【问题描述】：

我有一张桌子multi_app_documentation.nsma1_ans员工以两位数和四位数字年份格式输入日期。当我尝试使用 TO_DATE 转换它时，我的 WHERE 语句中出现错误：

错误：“DD”的无效值“/1” 详细信息：值必须是整数。

当员工不使用四位数年份时，我怎样才能让我的查询工作？他们可以输入 01232023 或 01/23/23。我假设我必须编写一个函数。作为 Postgresql 的新手，这不是我以前没有做过的事情。任何帮助深表感谢。

SELECT 
CASE WHEN
multi_app_documentation.nsma1_code = 'DATE' 
THEN TO_DATE(multi_app_documentation.nsma1_ans, 'MMDDYYYY') END AS "Procedure Date", 

    ' ' AS "Case Confirmation Number",
    ip_visit_1.ipv1_firstname AS "Patient First", 
    ip_visit_1.ipv1_lastname AS "Patient Last", 
    visit.visit_sex AS "Patient Gender", 
    TO_CHAR(visit.visit_date_of_birth, 'MM/DD/YYYY') AS "DOB", 
    visit.visit_id AS "Account Number", 
    visit.visit_mr_num AS "MRN",
    ' ' AS "Module",
    ' ' AS "Signed off DT", 
    CASE WHEN
    multi_app_documentation.nsma1_code = 'CRNA' THEN multi_app_documentation.nsma1_ans END AS "Primary CRNA",
    ' ' AS "Secondary CRNA",
    ' ' AS "Primary Anesthesiologist",
' ' AS "Secondary Anesthesiologist",
' ' AS "Canceled Yes/No" 
FROM
    multi_app_documentation
    INNER JOIN ip_visit_1 ON multi_app_documentation.nsma1_patnum = ip_visit_1.ipv1_num
    INNER JOIN visit ON ip_visit_1.ipv1_num = visit.visit_id 
WHERE
multi_app_documentation.nsma1_code = 'DATE' AND TO_DATE(multi_app_documentation.nsma1_ans, 'MMDDYYYY') = CURRENT_DATE 

ORDER BY
ip_visit_1.ipv1_lastname;

【问题讨论】：

标签： postgresql

【解决方案1】：

一个快速而肮脏的解决方案。

SELECT
    CASE WHEN strpos('01232023', '/') > 0 THEN
        to_date('01/23/23', 'MM/DD/YYYY')
    ELSE
        to_date('01232023', 'MMDDYYYY')
    END AS dt;

01/23/2023

SELECT
    CASE WHEN strpos('01/23/23', '/') > 0 THEN
        to_date('01/23/23', 'MM/DD/YYYY')
    ELSE
        to_date('01232023', 'MMDDYYYY')
    END AS dt;

01/23/2023

尽管您最好将这些值存储在 date 中，使用上面的方法转换为 date。

【讨论】：