【发布时间】:2023-01-13 23:36:49
【问题描述】:
我的问题已在 Stackoverflow 中被反复询问和回答,但似乎没有一个解决方案对我有用。能否请你帮忙?这是我使用 dput 的数据示例。 dput(sample_n(CA_Complication, 20))
structure(list(ID = c("101", "101", "101", "101", "101", "101",
"101", "101", "101", "101", "101", "101", "101", "101", "101",
"101", "101", "101", "101", "101"), AD = c("447", "243", "608",
"537", "1588", "302", "28", "1035", "755", "8", "1262", "95",
"1954", "231", "88", "1898", "1028", "669", "103", "773"), Date1 = structure(c(1367802000,
1324515600, 1404781200, 1391043600, 1621299600, 1340067600, 1291078800,
1489453200, 1456966800, 1278986400, 1544058000, 1295398800, 1637629200,
1321318800, 1293411600, 1623286800, 1485392400, 1417050000, 1296522000,
1431997200), tzone = "UTC", class = c("POSIXct", "POSIXt")),
Date2 = c("41400.041666666701", "40913.041666666701",
"41828.041666666701", "41697.041666666701", "44334.041666666701",
"41080.041666666701", "40512.041666666701", "42901.041666666701",
"42443.041666666701", "40372.041666666701", "43535.041666666701",
"40197.041666666701", "44523.041666666701", "40862.041666666701",
"40539.041666666701", "44357.041666666701", "42817.041666666701",
"42016.041666666701", "40575.041666666701", "42143.041666666701"
), procedure = c("CH-0447", "CH-0243", "CH-0608",
"CH-0537", "CH-1588", "CH-0302", "CH-0028",
"CH-1035", "CH-0755", "CH-0008", "CH-1262",
"CH-0095", "CH-1954", "CH-0231", "CH-0088",
"CH-1898", "CH-1028", "CH-0669", "CH-0103",
"CH-0773"), PAT = c("101-447", "101-243", "101-608",
"101-537", "101-1588", "101-302", "101-28", "101-1035", "101-755",
"101-8", "101-1262", "101-95", "101-1954", "101-231", "101-88",
"101-1898", "101-1028", "101-669", "101-103", "101-773"),
LOMP17 = c(NA, NA, NA, NA, 309015, NA, NA, 409030, NA, NA,
209015, NA, 209005, NA, NA, 209005, NA, NA, NA, NA), LOMP = c(30055,
140020, 60020, 10005, NA, 90005, 30005, NA, 10005, NA, NA,
10005, NA, 30005, 20005, NA, NA, 10005, 30060, 100010)), class = c("tbl_df",
"tbl", "data.frame"), row.names = c(NA, -20L))
如您所见,有两个日期列在 excel 中看起来相似(两者的单元格格式均为 date: *14-03-2012。但是,当我在 R 中打开文件时,Date1 的类型为 Dttm,而 Date2 为字符。我可以得到我想要的使用以下代码的日期 1 的日期格式:
library("anytime")
anydate(mydata$Date1) #yeilds date as yyyy-mm-dd,hh:mm:ss
mydata$Date1 <- substring(mydata$Date1,1,10) # Remove hh:mm:ss
mydata$Date1 <- format(as.Date(mydata$Date1,'%Y-%m-%d'),'%d-%m-%Y')
class(mydata$Date1) #character
但是我无法获得所需格式的第二个 Date 列。如果我使用上面的代码,它会引入许多 NA。我还使用了此代码 openxlsx::convertToDateTime(mydata$Date2) 导致以下错误:NAs introduced by coercion。
然后我尝试了这个:
library(tibble)
library(janitor)
excel_numeric_to_date(as.numeric(as.character(mydata$Date2), date_system = "modern"))
这导致了这个警告信息:
In excel_numeric_to_date(as.numeric(as.character(mydata$Date2), :
NAs introduced by coercion
我也试过这个:
library("datetimeutils")
convert_date(mydata$Date2, type = "Excel")
Error in charToDate(x) :
character string is not in a standard unambiguous format
有人可以帮我吗?
【问题讨论】:
-
关键是先转换为数字,例如
as.Date(as.numeric(df$Date2), origin = "1899-12-30") -
@AndreWildberg 这是我收到的警告:强制引入的 NA。我刚刚意识到只有当日期等于 09-09-1809 时才会引入 NA。在此数据集中,似乎如果日期未知,则使用 09-09-1809,不幸的是我无法更改它。
-
您能否将失败的行之一包含到您的示例中?
-
@AndreWildberg 我将 dput 从 10 更新为 20。在 Date2 中,第 16 个和第 20 个值等于 09-09-1809。但对我来说,这里提供的数字并不清楚。我希望它有所帮助。
标签: r excel date lubridate posixct