如何按 doc_count 对存储桶进行排序？

Question

GET /civile/_search
{
  "size": 0,
  "query": {
    "match": {
      "distretto": "MI"
    }
  },
  "aggs": {
    "our_buckets": {
      "composite": {
        "size": 1000,
        "sources": [
          { "codiceoggetto": { "terms": { "field": "codiceoggetto.keyword", "order": "desc" } } }
        ]
      }
    }
  }
}

我的 Elasticsearch 查询通过 distretto =“MI”匹配文档。 使用 size = 0 我隐藏结果。

但最重要的是我定义了 our_buckets 聚合。 它返回 1000 个键并在 codiceoggetto.keyword 字段上执行“分组依据”。

现在我想按 doc_count 排序我的存储桶结果！我能怎么做？

这里的回应

{
  "took" : 20,
  "timed_out" : false,
  "_shards" : {
    "total" : 1,
    "successful" : 1,
    "skipped" : 0,
    "failed" : 0
  },
  "hits" : {
    "total" : {
      "value" : 10000,
      "relation" : "gte"
    },
    "max_score" : null,
    "hits" : [ ]
  },
  "aggregations" : {
    "our_buckets" : {
      "after_key" : {
        "codiceoggetto" : "010001"
      },
      "buckets" : [
        {
          "key" : {
            "codiceoggetto" : "490999"
          },
          "doc_count" : 3
        },
        {
          "key" : {
            "codiceoggetto" : "481312"
          },
          "doc_count" : 1
        },

Answer 1

你可以使用bucket_sort来完成

{
  "size": 0,
  "query": {
    "match": {
      "distretto": "MI"
    }
  },
  "aggs": {
    "our_buckets": {
      "composite": {
        "size": 1000,
        "sources": [
          {
            "codiceoggetto": {
              "terms": {
                "field": "codiceoggetto.keyword",
                "order": "desc"
              }
            }
          }
        ]
      },
      "aggs": {
        "sort_by_count": {
          "bucket_sort": {
            "sort": [
              {
                "_count": {
                  "order": "desc"
                }
              }
            ]
          }
        }
      }
    }
  }
}