当我希望操作可切换时，我的代码一直默认为加法

Question

我是 C++ 的初学者，我正在尝试编写一个可以执行所有 4 种基本数学运算的计算器。问题是，它一直默认为加法，事实上，我可以将任何东西放入你应该放置操作符号的地方，并且它会加法。

#include <iostream>
using namespace std;
int main()
{
    string Operation;
    float Number1{}, Number2{};
    float Answer1, Answer2, Answer3, Answer4;

    cout << "Calculator 1.0" << endl;
    cout << "Enter Equation: ";
    cin >> Number1 >> Operation >> Number2;

    if (Operation == "Plus" or "plus" or "Add" or "add" or "+")
    {
        Answer1 = Number1 + Number2;
        cout << Number1 << " + " << Number2 << " = " << Answer1;
    }
    else
    {
        if (Operation == "Minus" or "minus" or "-")
        {
            Answer2 = Number1 - Number2;
            cout << Number1 << " - " << Number2 << " = " << Answer2;
        }
        else
        {
            if (Operation == "times" or "Times" or "*" or "x")
            {
                Answer3 = Number1 * Number2;
                cout << Number1 << " x " << Number2 << " = " << Answer3;
            }
            else
            {
                if (Operation == "/")
                {
                    Answer4 = Number1 / Number2;
                    cout << Number1 << " / " << Number2 << " = " << Answer4;
                }
            }
        }
    }
}

我试图将操作与第一个 if 语句分开并制作单独的操作，但所做的只是同时打印两者，就好像 if 语句不存在并且它只是执行所有代码而不管它说了什么.

Answer 1

c++ 不是英语，这个

if (Operation == "Minus" or "minus" or "-")

不做你想做的，你需要

if (Operation == "Minus" or Operatin == "minus" or Operation == "-")

以及其他地方的类似修复