从列表中删除号码

Question

程序应该在区间内产生10个随机数 [1;3]，将它们存储在一个列表中，并打印列表的内容 屏幕上！用户应该能够在 interval [1;3]，程序应该删除所有出现的地方 从列表中删除这个数字，然后打印修改后的列表 屏幕上！

我尝试用两种方法运行以下程序，但它们没有产生我想要的最终列表。

第一次尝试：

import random

random_list=[]
number=0
deleted_number=0
final_list=[]

for i in range(10):
    number=random.randint(1,3)
    random_list.append(number)
print(random_list)
deleted_number=input('Give a number from 1 to 3, that you want to delete from the list.')
final_list = list(set(random_list) - set(deleted_number))
print('The new list without the deleted values:')
print(final_list)

第二次尝试：

import random
random_list=[]
number=0
deleted_number=0
final_list=[]

for i in range(10):
    number=random.randint(1,3)
    random_list.append(number)
print(random_list)
deleted_number=input('Give a number from 1 to 3, that you want to delete from the list.')
final_list = [item for item in random_list if item != deleted_number]
print('The new list without the deleted values:')
print(final_list)

提前谢谢你的帮助。

Answer 1

您需要将用户输入从字符串转换为 int，如下所示：

deleted_number = int(input('Give a number from 1 to 3, that you want to delete from the list: '))

和线

final_list = [item for item in random_list if item != deleted_number]

第二次尝试是正确的