删除所有 xml 父项，保留具有特定子项的项（正则表达式）

Question

我很想删除每个不包含特定值的父母，例如

<drawableDictionary>l_njdocklod12</drawableDictionary>

下面的 XML 示例：

<?xml version="1.0" encoding="UTF-8"?>
<CMapTypes name="lodetnjdock_wh1">
 <extensions />
 <archetypes>
  <Item type="CBaseArchetypeDef">
   <lodDist value="550" />
   <flags value="0" />
   <specialAttribute value="0" />
   <bbMin x="-12.3383" y="-6.42445" z="-13.3852" />
   <bbMax x="12.3382" y="6.42445" z="13.3852" />
   <bsCentre x="-5.05447E-05" y="2.38419E-06" z="0" />
   <bsRadius value="19.3046" />
   <hdTextureDist value="0" />
   <name>hash_349C91C8</name>
   <textureDictionary>njdocklod04</textureDictionary>
   <clipDictionary />
   <drawableDictionary>lodnjdocksuper11_grp</drawableDictionary>
   <physicsDictionary>nj_docks</physicsDictionary>
   <assetType>ASSET_TYPE_DRAWABLEDICTIONARY</assetType>
   <assetName>hash_349C91C8</assetName>
   <extensions />
  </Item>
  <Item type="CBaseArchetypeDef">
   <lodDist value="550" />
   <flags value="0" />
   <specialAttribute value="0" />
   <bbMin x="-5.6393" y="-5.45088" z="-4.9861" />
   <bbMax x="5.6393" y="5.45088" z="4.9861" />
   <bsCentre x="0" y="-4.76837E-07" z="4.76837E-07" />
   <bsRadius value="9.29382" />
   <hdTextureDist value="0" />
   <name>hash_46EE366B</name>
   <textureDictionary>njdocklod12</textureDictionary>
   <clipDictionary />
   <drawableDictionary>l_njdocklod12</drawableDictionary>
   <physicsDictionary>nj_docks</physicsDictionary>
   <assetType>ASSET_TYPE_DRAWABLEDICTIONARY</assetType>
   <assetName>hash_46EE366B</assetName>
   <extensions />
  </Item>
  <Item type="CBaseArchetypeDef">
   <lodDist value="550" />
   <flags value="0" />
   <specialAttribute value="0" />
   <bbMin x="-11.8993" y="-34.8797" z="-4.27972" />
   <bbMax x="11.8992" y="34.8796" z="4.29434" />
   <bsCentre x="-2.76566E-05" y="-1.52588E-05" z="0.0073123" />
   <bsRadius value="37.102" />
   <hdTextureDist value="0" />
   <name>hash_52EAB9C8</name>
   <textureDictionary>njdocklod10</textureDictionary>
   <clipDictionary />
   <drawableDictionary>lodnjdocksuper05_grp</drawableDictionary>
   <physicsDictionary>nj_docks</physicsDictionary>
   <assetType>ASSET_TYPE_DRAWABLEDICTIONARY</assetType>
   <assetName>hash_52EAB9C8</assetName>
   <extensions />
  </Item>
 </archetypes>
 <name>nj_docks_lod</name>
 <dependencies />
 <compositeEntityTypes itemType="CCompositeEntityType" />
</CMapTypes>

期望的结果

<?xml version="1.0" encoding="UTF-8"?>
<CMapTypes name="lodetnjdock_wh1">
 <extensions />
 <archetypes>
  <Item type="CBaseArchetypeDef">
   <lodDist value="550" />
   <flags value="0" />
   <specialAttribute value="0" />
   <bbMin x="-5.6393" y="-5.45088" z="-4.9861" />
   <bbMax x="5.6393" y="5.45088" z="4.9861" />
   <bsCentre x="0" y="-4.76837E-07" z="4.76837E-07" />
   <bsRadius value="9.29382" />
   <hdTextureDist value="0" />
   <name>hash_46EE366B</name>
   <textureDictionary>njdocklod12</textureDictionary>
   <clipDictionary />
   <drawableDictionary>l_njdocklod12</drawableDictionary>
   <physicsDictionary>nj_docks</physicsDictionary>
   <assetType>ASSET_TYPE_DRAWABLEDICTIONARY</assetType>
   <assetName>hash_46EE366B</assetName>
   <extensions />
  </Item>
 </archetypes>
 <name>nj_docks_lod</name>
 <dependencies />
 <compositeEntityTypes itemType="CCompositeEntityType" />
</CMapTypes>

我想实现这个使用正则表达式，使用 Notepad++，因为我离这里的舒适区很远，到目前为止这对我有用。

Answer 1

完成这项工作的工具是 XSLT。这是一个非常简单的转换：一个复制所有内容不变的身份模板加上一个删除不需要的项目的规则：

<xsl:template match="Item[not(drawableDictionary='l_njdocklod12')]"/>

在 XSLT 3.0 中，您可以通过编写获得标识模板

<xsl:mode on-no-match="shallow-copy"/>

在旧版本中，写

<xsl:template match="@*|node()">
  <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>

Answer 2

可以搜索所有不包含该值的<Item>元素 l_njdocklod12 使用这个正则表达式：
<Item((?!l_njdocklod12).)*?</Item>$

请注意，(?! 是前瞻性的，以验证您的字符串不存在。
我使用*? 进行非贪婪匹配。

确保选中 . matches newline。

要删除找到的匹配项，请将它们替换为空字符串。