Laravel Eloquent 不良建筑查询

Question

我构建了一个 Eloquent 查询，如下所示。

DB::connection()->enableQueryLog();
$reportSelect = Payment::join('users', 'users.id', '=', 'payment.user_id')
    ->join('user_information', 'user_information.user_id', '=', 'users.id')
    ->join('register_type', 'register_type.id', '=', 'payment.register_type_id')
    ->join('payment_type', 'payment_type.id', '=', 'payment.payment_type_id')
    ->select(
        'payment.id',
        'user_information.full_name as user_full_name',
        'register_type.register_type',
        'payment_type.payment_type',
        'payment.created_at',
        'payment.updated_at'
    );

$date_start = '2021-7-6';
$date_end = '2021-7-10';

$reportSelect->whereBetween('payment.created_at', [$date_start, $date_end])->get();

$queries = DB::getQueryLog();

return $queries;

这个SQL查询日志的结果如下。

SELECT
    'payment'.'id',
    'user_information'.'full_name' as 'user_full_name',
    'register_type'.'register_type',
    'payment_type'.'payment_type',
    'payment'.'created_at',
    'payment'.'updated_at'
FROM 'payment'
    inner join 'users' on 'users'.'id' = 'payment'.'user_id'
    inner join 'user_information' on 'user_information'.'user_id' = 'users'.'id'
    inner join 'register_type' on 'register_type'.'id' = 'payment'.'register_type_id'
    inner join 'payment_type' on 'payment_type'.'id' = 'payment'.'payment_type_id'
WHERE 'payment'.'created_at' between ? and ?

为什么不在 where 子句中设置我的 date_start 参数和 date_end 参数，而是放置字符 ?。提前致谢;对不起我的英语。

Answer 1

//需要加上$date_start和$date_end的日期方法

$date_start = date('2021-7-6'); $date_end = date('2021-7-10');

$reportSelect->whereBetween('payment.created_at', [$date_start, $date_end])->get();