Python按名称中特定点的数值对列表进行排序答案

【问题标题】：Python sort list by numerical value at specific point in namePython按名称中特定点的数值对列表进行排序
【发布时间】：2022-12-17 11:29:59
【问题描述】：

我有一个清单：

'45MO_221115_High4_d-1.tif', '45MO_221115_High4_d-2.tif', '45MO_221115_High4_d0.tif', '45MO_221115_High4_d1.tif', '45MO_221115_High4_d3.tif', '45MO_221115_Low1_d-1.tif', '45MO_221115_Low1_d-2.tif', '45MO_221115_Low1_d0.tif', '45MO_221115_Low1_d1.tif', '45MO_221115_Low1_d3.tif', '45MO_221115_Med2_d-1.tif', '45MO_221115_Med2_d-2.tif', '45MO_221115_Med2_d0.tif', '45MO_221115_Med2_d1.tif', '45MO_221115_Med2_d3.tif'

我想对列表进行排序，以便第 -2 天图像 (d-2) 出现在第 -1 天 (d-1) 之前。所有 d-2 都可以出现在每组的开头，以便：

'45MO_221115_High4_d-2.tif', '45MO_221115_High4_d-1.tif', '45MO_221115_High4_d0.tif', '45MO_221115_High4_d1.tif', '45MO_221115_High4_d3.tif', '45MO_221115_Low1_d-2.tif', '45MO_221115_Low1_d-1.tif', '45MO_221115_Low1_d0.tif', '45MO_221115_Low1_d1.tif', '45MO_221115_Low1_d3.tif', '45MO_221115_Med2_d-2.tif', '45MO_221115_Med2_d-1.tif', '45MO_221115_Med2_d0.tif', '45MO_221115_Med2_d1.tif', '45MO_221115_Med2_d3.tif'

或者所有的 d-2 都可以在开头分组：

  '45MO_221115_High4_d-2.tif', '45MO_221115_Low1_d-2.tif', '45MO_221115_Med2_d-2.tif', '45MO_221115_High4_d-1.tif',  '45MO_221115_Low1_d-1.tif', etc'

两种变体都很好。第二个可能更容易。

【问题讨论】：

标签： python list sorting

【解决方案1】：

匹配第二个输出的一种方法（首先是 d-2，然后是 d-1，然后是其余的）是：

res = sorted(lst, key=lambda s: ('d-2' not in s, 'd-1' not in s))
print(res)

输出

['45MO_221115_High4_d-2.tif',
 '45MO_221115_Low1_d-2.tif',
 '45MO_221115_Med2_d-2.tif',
 '45MO_221115_High4_d-1.tif',
 '45MO_221115_Low1_d-1.tif',
 '45MO_221115_Med2_d-1.tif',
 '45MO_221115_High4_d0.tif',
 '45MO_221115_High4_d1.tif',
 '45MO_221115_High4_d3.tif',
 '45MO_221115_Low1_d0.tif',
 '45MO_221115_Low1_d1.tif',
 '45MO_221115_Low1_d3.tif',
 '45MO_221115_Med2_d0.tif',
 '45MO_221115_Med2_d1.tif',
 '45MO_221115_Med2_d3.tif']

【讨论】：