检查时间距离是否在不同时间之间

Question

我从我的函数中使用 javascript 和 php 进行了倒计时，倒计时有效，但现在我想要 3 个选项：

1. 如果倒计时超过 24 小时，请显示 te selector.next(".countdown").html(expiry); date

2. 如果倒计时为 6 小时或更短时间，请显示计时器selector.next(".countdown").html(days + "d " + hours + "h " + minutes + "m " + seconds + "s ");

3. 否则倒计时小于0表示endend selector.next(".countdown").html(<p>Closed</p>);

   $(".expiry").each(function() {
       var expiry = new Date($(this).text());
       var selector = $(this)
       var x = setInterval(function() {
           var currentDateObj = new Date();
           var numberOfMlSeconds = currentDateObj.getTime();
           var addMlSeconds = 60 * 60 * 1000;
           var now = new Date(numberOfMlSeconds - addMlSeconds);
   
           var distance = expiry - now;
           var days = Math.floor(distance / (1000 * 60 * 60 * 24));
           var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
           var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
           var seconds = Math.floor((distance % (1000 * 60)) / 1000);
   
           if( distance >= 86400000 && distance < 21600000){
             selector.next(".countdown").html(expiry);  
           }else if ( distance <= 21600000 && distance > 0){
             selector.next(".countdown").html(days + "d " + hours + "h " + minutes + "m " + seconds + "s "); 
           }else{
             selector.next(".countdown").html('<p>error</p>');
           }
       }, 1000);
   });
   

Answer 1

您的 IF 语句的第一行是否正确？你想检查它是否在这两个数字之间吗？如果是这样，条件不应该是：

if(distance <= 86400000 && distance > 21600000)

IE。如果距离是小于或等于86400000 和比...更棒21600000

目前你正在检查 distance 是否是大于或等于 86400000和小于 21600000这总是会产生错误

编辑 查看带有条件的完整 if 语句块大于 86400000

if (distance > 86400000) {
    selector.next(".countdown").html('<p>A LOOOOOONG Way off expiring</p>');            
}
else if (distance <= 864000000 && distance > 432000000) { 
    selector.next(".countdown").html(expiry); 
}
else if (distance <= 432000000 && distance > 0) {
    selector.next(".countdown").html(days + "d " + hours + "h " + minutes + "m " + seconds + "s "); 
}
else if (distance < 0) { 
    selector.next(".countdown").html('<p>afgelopen</p>'); 
}
else { 
    selector.next(".countdown").html('<p>Error</p>'); 
}