【发布时间】:2022-12-08 02:22:16
【问题描述】:
亲爱的人们,
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btnSubmit_Click 无法处理代码并在 MySql 语法错误中显示错误。
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我只想将文本框输入插入数据库,同时从数据库中选择 Cus_ID 并重新插入到 Orders 表中。
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最后显示订单ID
使用系统; 使用 System.Collections.Generic; 使用 System.ComponentModel; 使用系统数据; 使用系统绘图; 使用 System.Linq; 使用系统文本; 使用 System.Threading.Tasks; 使用 System.Windows.Forms; 使用 MySql.Data.MySqlClient;
命名空间项目 { 公共部分类 CoffeeMania:表格 { 公共 CoffeeMania() { 初始化组件(); }
private void CoffeeMania_Load(object sender, EventArgs e) { cmbBranchArea.Items.Add("PJ"); cmbBranchArea.Items.Add("KL"); cmbCusGender.Items.Add("Male"); cmbCusGender.Items.Add("Female"); } private void btnSubmit_Click(object sender, EventArgs e) { string dburl = System.Configuration.ConfigurationManager.ConnectionStrings["dburl"].ConnectionString; MySqlConnection conn = new MySqlConnection(dburl); int qty = int.Parse(txtAmericano.Text + txtCappuccino.Text + txtMocha.Text + txtEspresso.Text + txtLatte.Text); string sql = "INSERT INTO customer(Cus_Name, Cus_Gender, Cus_Phone) VALUES('"+txtCusName+"', '"+cmbCusGender.SelectedItem+"', '"+txtCusPhone.Text+"';)"; string sql2 = "select Cus_ID from customer where Cus_Name='" + txtCusName.Text + "' and Cus_Gender='" + cmbCusGender.SelectedItem + "' and Cus_Phone='" + txtCusPhone.Text + "'; "; try { conn.Open(); MySqlCommand comm = new MySqlCommand(sql, conn); int record = Convert.ToInt32(comm.ExecuteNonQuery()); Console.WriteLine(record); MySqlCommand comm2 = new MySqlCommand(sql2, conn); MySqlDataReader reader2 = comm2.ExecuteReader(); if(reader2.Read()) { int CusID = Convert.ToInt32(reader2["Cus_ID"]); string sql3 = "INSERT INTO orders(Orders_Qty, Cus_ID, Branch_ID) VALUES('" + qty + "', '" + CusID + "', '" + cmbBranchArea.SelectedItem + "';)"; MySqlCommand comm3 = new MySqlCommand(sql3, conn); int record3 = Convert.ToInt32(comm3.ExecuteNonQuery()); Console.WriteLine(record3); string sql4 = "select Orders_ID from orders where Cus_ID='" + CusID + "';"; MySqlCommand comm4 = new MySqlCommand(sql4, conn); MySqlDataReader reader4 = comm4.ExecuteReader(); if(reader4.Read()) { MessageBox.Show("Your Order ID is: " + reader4["Orders_ID"]); } } lblShowVoteResult.Text = "Successfully submitted"; comm.Dispose(); conn.Close(); } catch(MySqlException ex) { MessageBox.Show(ex.Message); } } }}
【问题讨论】:
标签: c# mysql winforms mysqlcommand