至少一个，至少没有一个答案

【问题标题】：Atleast one and atleast not one至少一个，至少没有一个
【发布时间】：2022-01-13 08:05:40
【问题描述】：

要求：

对于策略：至少一件商品 (RAP03.propid) 有折扣 (rap14.covid = 'SS') 并且至少一件商品没有折扣 (SS)。假设我们有一个策略 (rap01.plcy) ，并且使用这个策略我们有 2 个项目 (rap03.propid)。因此，一件物品 SS 应该在那里，一件物品 SS 不应该在那里。我在下面尝试过，但记录为零。有什么办法可以同时检查这两种情况。

我们还必须尊重政策和项目 (PROPID)。一个 propid 必须包含 SS，但另一个 propid 不得包含 SS。

要求的结果：

PLCY, PROPID, COVID
000000967428613 010 SS
000000967428613 011 BB

AND EXISTS
  (SELECT 1
    /*+ use_hash(RAP03 rap14) */
  FROM rap03
JOIN rap14
ON  rap14.j31_pt_line_cat_cd = rap01.j01_PT_LINE_CAT_CD 
AND rap14.j31_pt_cdb_part_id = rap01.j01_PT_CDB_PART_ID
AND rap14.j31_pt_state_cd    = rap01.j01_PT_STATE_CD
AND rap14.plcy               = RAP01.plcy
AND rap14.propid             = RAP03.propid
AND trim(rap14.covid)        = 'SS'
AND tt.JA2_EFFDT_T BETWEEN rap14.enddt_t AND (rap14.dropdt_t - 1)
--
  WHERE RAP03.J12_PT_LINE_CAT_CD = RAP01.J01_PT_LINE_CAT_CD
  AND RAP03.J12_PT_CDB_PART_ID   = RAP01.J01_PT_CDB_PART_ID
  AND RAP03.J12_PT_STATE_CD      = RAP01.J01_PT_STATE_CD
  AND RAP03.PLCY                 = RAP01.PLCY
  AND tt.JA2_EFFDT_T BETWEEN rap03.adddt_t AND (rap03.dropdt_t  - 1)
  ) 
--
AND NOT EXISTS
  (SELECT 1
    /*+ use_hash(RAP03 rap14) */
  FROM rap03
JOIN rap14
ON  rap14.j31_pt_line_cat_cd = rap01.j01_PT_LINE_CAT_CD 
AND rap14.j31_pt_cdb_part_id = rap01.j01_PT_CDB_PART_ID
AND rap14.j31_pt_state_cd    = rap01.j01_PT_STATE_CD
AND rap14.plcy               = RAP01.plcy
AND rap14.propid             = RAP03.propid
AND trim(rap14.covid)        = 'SS'
AND tt.JA2_EFFDT_T BETWEEN rap14.enddt_t AND (rap14.dropdt_t - 1)
--
  WHERE RAP03.J12_PT_LINE_CAT_CD = RAP01.J01_PT_LINE_CAT_CD
  AND RAP03.J12_PT_CDB_PART_ID   = RAP01.J01_PT_CDB_PART_ID
  AND RAP03.J12_PT_STATE_CD      = RAP01.J01_PT_STATE_CD
  AND RAP03.PLCY                 = RAP01.PLCY
  AND tt.JA2_EFFDT_T BETWEEN rap03.adddt_t AND (rap03.dropdt_t  - 1)
  )

【问题讨论】：

请edit 提出minimal reproducible example 的问题，包括：CREATE TABLE 表的声明；一些样本数据的INSERT 语句；您正在使用的我们可以运行的查询的完整（和最小）示例；问题的英文（非代码）解释；您的代码的问题/错误；以及该样本数据的预期输出。

标签： sql oracle

【解决方案1】：

您当前有WHERE EXISTS(query) AND NOT EXISTS(query)，并且两个查询是相同的；这总是错误的。

我认为你想要的逻辑是WHERE (at least one record exists with 'SS') AND (at least one record exists that's not 'SS')

AND EXISTS
  (SELECT 1
    /*+ use_hash(RAP03 rap14) */
  FROM rap03
JOIN rap14
ON  rap14.j31_pt_line_cat_cd = rap01.j01_PT_LINE_CAT_CD 
AND rap14.j31_pt_cdb_part_id = rap01.j01_PT_CDB_PART_ID
AND rap14.j31_pt_state_cd    = rap01.j01_PT_STATE_CD
AND rap14.plcy               = RAP01.plcy
AND rap14.propid             = RAP03.propid
AND trim(rap14.covid)        = 'SS'
AND tt.JA2_EFFDT_T BETWEEN rap14.enddt_t AND (rap14.dropdt_t - 1)
--
  WHERE RAP03.J12_PT_LINE_CAT_CD = RAP01.J01_PT_LINE_CAT_CD
  AND RAP03.J12_PT_CDB_PART_ID   = RAP01.J01_PT_CDB_PART_ID
  AND RAP03.J12_PT_STATE_CD      = RAP01.J01_PT_STATE_CD
  AND RAP03.PLCY                 = RAP01.PLCY
  AND tt.JA2_EFFDT_T BETWEEN rap03.adddt_t AND (rap03.dropdt_t  - 1)
  ) 
--

AND EXISTS -- CHANGE HERE (NOT removed)

  (SELECT 1
    /*+ use_hash(RAP03 rap14) */
  FROM rap03
JOIN rap14
ON  rap14.j31_pt_line_cat_cd = rap01.j01_PT_LINE_CAT_CD 
AND rap14.j31_pt_cdb_part_id = rap01.j01_PT_CDB_PART_ID
AND rap14.j31_pt_state_cd    = rap01.j01_PT_STATE_CD
AND rap14.plcy               = RAP01.plcy
AND rap14.propid             = RAP03.propid

AND trim(rap14.covid)       <> 'SS'  -- CHANGE HERE (= becomes <>)

AND tt.JA2_EFFDT_T BETWEEN rap14.enddt_t AND (rap14.dropdt_t - 1)
--
  WHERE RAP03.J12_PT_LINE_CAT_CD = RAP01.J01_PT_LINE_CAT_CD
  AND RAP03.J12_PT_CDB_PART_ID   = RAP01.J01_PT_CDB_PART_ID
  AND RAP03.J12_PT_STATE_CD      = RAP01.J01_PT_STATE_CD
  AND RAP03.PLCY                 = RAP01.PLCY
  AND tt.JA2_EFFDT_T BETWEEN rap03.adddt_t AND (rap03.dropdt_t  - 1)
  )

将它们结合起来可以减少代码，但实际上可能会更慢，因为它不能在找到的第一条记录处“停止”...

AND EXISTS
(
  SELECT 1
    /*+ use_hash(RAP03 rap14) */
  FROM rap03
  JOIN rap14
    ON  rap14.j31_pt_line_cat_cd = rap01.j01_PT_LINE_CAT_CD 
    AND rap14.j31_pt_cdb_part_id = rap01.j01_PT_CDB_PART_ID
    AND rap14.j31_pt_state_cd    = rap01.j01_PT_STATE_CD
    AND rap14.plcy               = RAP01.plcy
    AND rap14.propid             = RAP03.propid
    AND tt.JA2_EFFDT_T BETWEEN rap14.enddt_t AND (rap14.dropdt_t - 1)
--
  WHERE RAP03.J12_PT_LINE_CAT_CD = RAP01.J01_PT_LINE_CAT_CD
    AND RAP03.J12_PT_CDB_PART_ID   = RAP01.J01_PT_CDB_PART_ID
    AND RAP03.J12_PT_STATE_CD      = RAP01.J01_PT_STATE_CD
    AND RAP03.PLCY                 = RAP01.PLCY
    AND tt.JA2_EFFDT_T BETWEEN rap03.adddt_t AND (rap03.dropdt_t  - 1)
  HAVING
    MAX(CASE WHEN TRIM(rap14.covid) = 'SS' THEN 1 ELSE 0 END) = 1
    AND
    MIN(CASE WHEN TRIM(rap14.covid) = 'SS' THEN 1 ELSE 0 END) = 0
)

可能有更好的方法来制定查询，但我们需要更多上下文（表定义、完整查询、完整逻辑解释等）。

【讨论】：

WHERE (至少有一条记录存在 'SS') AND (至少有一条记录不是 'SS') ，这在某种程度上是正确的。但有更多的扭曲。假设我们有一个策略 (rap01.plcy) ，并且使用这个策略我们有 2 个项目 (rap03.propid)。因此，一件物品 SS 应该在那里，一件物品 SS 不应该在那里。
@KaushalTalniya - 你现在似乎在问一个不同的问题。请开始一个新问题，但包括示例数据以演示您需要的场景和逻辑。可以在此处找到有关如何编写此类问题的一些有用建议：meta.stackoverflow.com/questions/333952/… 和 stackoverflow.com/help/minimal-reproducible-example
用期望的结果编辑了问题。
@kaushaltalniya 您需要包括源数据以及预期结果。您将从将问题简化为可以从中学习的更简单示例中受益。（请阅读我为您提供的两个链接，关于最小示例和可重现示例。）您应该提出新问题，而不是对现有问题进行实质性更改。