停止 2 次连续使用 discord.py答案

【问题标题】：Stop 2 consecutive uses discord.py停止 2 次连续使用 discord.py
【发布时间】：2022-12-03 20:42:44
【问题描述】：

我正在制作一个可以进行拍卖的不和谐机器人。所以我希望某人只出价一次，除非有人在他/她之后出价。

`async def bid(ctx): 

  embed1=discord.Embed(description= f'Bid has been placed by {ctx.author}', title='bid placed')

  await ctx.send(embed=embed1)

       `

这就是我到目前为止所做的。

【问题讨论】：

标签： discord discord.py

【解决方案1】：

您可以将作者 ID 放在一个变量中：

bidderid = 0 #this will reset whenever your bot restarts
@client.command()
async def bid(ctx):
    global bidderid
    if ctx.author.id != bidderid: #if it is not the same bidder
        bidderid = ctx.author.id
        embed1=discord.Embed(description= f'Bid has been placed by {ctx.author}', title='bid placed')
        await ctx.send(embed=embed1)
    else: #if it is the same bidder
        await ctx.send('You cannot bid twice in a row!') #replace with whatever message

注意：它不一定是id，你可以存储ctx.author而不是，想法是一样的

【讨论】：

【解决方案2】：

# create an empty list to store user IDs
user_ids = []

async def bid(ctx):
    # check if the user's ID is in the list of user IDs
    if ctx.author.id in user_ids:
        # if the user has already placed a bid, send a message to let them know
        embed1 = discord.Embed(description= f'{ctx.author}, you have already placed a bid', title='bid not placed')
        await ctx.send(embed=embed1)
    else:
        # if the user has not placed a bid, add their ID to the list of user IDs and send a message to confirm their bid
        user_ids.append(ctx.author.id)
        embed1 = discord.Embed(description= f'Bid has been placed by {ctx.author}', title='bid placed')
        await ctx.send(embed=embed1)

【讨论】：