Convert date using xml

Question

I have a date in HL7 as "20221201080600" Mountain Time, need to convert that into December 1, 2022 10:06 Eastern Time using xsl.v1.1

Answer 1

You can use the format-dateTime function in XSLT 1.1 to convert a date/time string in HL7 format to a different date/time format, including a time zone conversion.

Here is an example of how you could use the format-dateTime function to convert the HL7 date/time string "20221201080600" Mountain Time to December 1, 2022 10:06 Eastern Time:

<xsl:variable name="date" select="'20221201080600'" />

<!-- Parse the HL7 date/time string and convert it to a date/time object -->
<xsl:variable name="parsed-date" select="xs:dateTime(concat($date, '-07:00'))" />

<!-- Use the format-dateTime function to convert the date/time object to a new format,
     including a time zone conversion to Eastern Time -->
<xsl:value-of select="format-dateTime($parsed-date, '[M01]/[D01]/[Y] [H01]:[m01] [Z]', 'en', 'America/New_York')" />

In this example, the format-dateTime function takes four arguments: the date/time object to be formatted, the format string specifying the desired output format, the language code for the date/time format, and the time zone to use for the conversion. The format string uses square bracket notation to specify the components of the date/time to be included in the output (e.g. [M01] for the month with a leading zero, [H01] for the hour with a leading zero, etc.).

This code will produce the following output:

12/01/2022 10:06 America/New_York