当值为零时如何使用枚举跳过索引计数？答案

【问题标题】：How to skip Index count using enumerate when value is zero?当值为零时如何使用枚举跳过索引计数？
【发布时间】：2022-12-02 05:41:10
【问题描述】：

I have currently one dict with key-value and one list with values. e.g.

data = {
    \'total\': {
        \'06724\': 0,
        \'06725\': 0,
        \'06726\': 0,
        \'06727\': 0,
        \'06712\': 22,
        \'06713\': 35,
        \'06714\': 108,
        \'06715\': 70,
        \'06716\': 0,
        \'06717\': 24,
        \'06718\': 0,
        \'06719\': 0,
        \'06720\': 0,
        \'06709\': 75,
        \'06710\': 123,
        \'06711\': 224,
        \'06708\': 28,
        \'06723\': 0,
        \'06721\': 0,
        \'06722\': 0
    },
    \'item_number\': [\'1\', \'2\', \'3\', \'4\', \'5\', \'6\', \'7\', \'8\', \'9\']
}

for Index, value in enumerate(data[\'total\'].values()):
    if value and value != \'0\':
        print(data[\'item_number\'][Index], value)

What I am trying to do is that I want to remove all values in \'total\' that has the value 0 meaning that it would only end up being 9 numbers which adds up to the item_number amount.

What I am trying to achieve is that I want print out:

Expected:

{
    \'1\': 22,
    \'2\': 35,
    \'3\': 108,
    \'4\': 70,
    \'5\': 24,
    \'6\': 75,
    \'7\': 123,
    \'8\': 224,
    \'9\': 28
}

where key is the item_number and the value is total.

However the code I am currently trying gives me the error:

    print(data[\'item_number\'][Index], value)
IndexError: list index out of range

which I believe is due to the Index increasing for each loop. I wonder how can I skip the counting increase if the value is 0?

标签： python

【解决方案1】：