discord.py command() got an unexpected keyword argument \'options\'

【问题标题】：discord.py command() got an unexpected keyword argument 'options'discord.py command() got an unexpected keyword argument \'options\'
【发布时间】：2022-12-02 01:42:00
【问题描述】：

So i am trying to make slash ban command in discord.py and i get this error: command() got an unexpected keyword argument 'options'

My code:

@tree.command(name="ban", description="Ban someone", options = [app_commands.choices(name="user", description="select user to ban", option_type=6, required=True)])
async def _ban(ctx, user: discord.Member):
    await user.ban(reason="NO reason")
    await ctx.send(f'Banned {user}! Reason: {reason}')

【问题讨论】：

标签： python discord.py

【解决方案1】：

@tree.command(name="ban", description="Ban someone")
async def _ban(ctx, user: discord.Member):
    await user.ban(reason="NO reason")
    await ctx.send(f'Banned {user}! Reason: {reason}')

If you are only using discord.py, which i assume so, user: discord.Member is enough. options = [app_commands.choices( isn't a thing.

Read the docs on @discord.app_commands.CommandTree.command

The real use of app_commands.choices looks like this:

@tree.command(name='command')
@app_commands.choices(option=[
  app_commands.Choice(name='option1', value='1'),
  app_commands.Choice(name='option2', value='2'),
])
async def command(interaction: discord.Interaction, option: app_commands.Choice[str]):
    if option.value == '1':
        #chosen option was option1
    elif option.value == '2':
        #chosen option was option2

【讨论】：