在重复的元素名称中查找特定对象，python 和 json答案

【问题标题】：finding a specific object within duplicate element names, python with json在重复的元素名称中查找特定对象，python 和 json
【发布时间】：2022-12-01 00:00:37
【问题描述】：

我想从 objectAttributeValues 中获取 displayValue，其中 objectTypeAttributeId = 14

有多个这样的数组，objectTypeAttributeId = 14 的位置并不总是相同的。如何遍历每个数组以获得特定的 displayValue？

示例 json：

{
  "objectEntries": [{
      "attributes": [{
          "id": "5210",
          "objectAttributeValues": [{
            "displayValue": "10/Nov/22 3:33 PM",
            "referencedType": false,
            "searchValue": "2022-11-10T15:33:49.298Z",
            "value": "2022-11-10T15:33:49.298Z"
          }],
          "objectId": "1201",
          "objectTypeAttributeId": "12"
        },
        {
          "id": "5213",
          "objectAttributeValues": [{
            "displayValue": "02f9ed75-b416-49d0-8515-0601581158e5",
            "referencedType": false,
            "searchValue": "02f9ed75-b416-49d0-8515-0601581158e5",
            "value": "02f9ed75-b416-49d0-8515-0601581158e5"
          }],
          "objectId": "1201",
          "objectTypeAttributeId": "14"
        },
        {
          "id": "5212",
          "objectAttributeValues": [{
            "displayValue": "",
            "referencedType": false,
            "searchValue": "",
            "value": ""
          }],
          "objectId": "1201",
          "objectTypeAttributeId": "11"
        }
      ]
    },
    {
      "attributes": [{
          "id": "4263",
          "objectAttributeValues": [{
            "displayValue": "427904c5-e2c8-4735-bc38-4013928cd043",
            "referencedType": false,
            "searchValue": "427904c5-e2c8-4735-bc38-4013928cd043",
            "value": "427904c5-e2c8-4735-bc38-4013928cd043"
          }],
          "objectId": "1011",
          "objectTypeAttributeId": "14"
        },
        {
          "id": "4262",
          "objectAttributeValues": [{
            "displayValue": "",
            "referencedType": false,
            "searchValue": "",
            "value": ""
          }],
          "objectId": "1011",
          "objectTypeAttributeId": "11"
        }
      ]
    }
  ]
}

对于此示例查询，值将是：

02f9ed75-b416-49d0-8515-0601581158e5
427904c5-e2c8-4735-bc38-4013928cd043

到目前为止，这是我的代码：

from jira import JIRA
import requests
import json

base_url = "url"
auth = basic_auth=('user', 'pass')

headers = {
  "Accept": "application/json"
}

pages = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]


for page in pages:
    response = requests.request("GET",base_url + '?page=' + str(page),headers=headers,auth=auth)
    all_output = json.dumps(json.loads(response.text), sort_keys=True, indent=4, separators=(",", ": "))
    output_dict = json.loads(response.text)
    output_list = output_dict["objectEntries"]
    for outputs in output_list:
        print(outputs["attributes"][0]["objectId"])
        print(outputs["name"])
        print(outputs["objectKey"])
        print(outputs["attributes"][0]["objectAttributeValues"][0]["displayValue"])
        print('\n')

老实说，我什至不知道从哪里开始，所以我还没有尝试太多。任何建议，将不胜感激！！

【问题讨论】：

标签： python json

【解决方案1】：

你可以浏览你的 JSON 字典并继续每个条目，直到你得到你感兴趣的条目。

# lets browse top level entries of your array
for e1 in outputs["objectEntries"]:
    # for each of those entries, browse the entries in the attribute section
    for e2 in e1["attributes"]:
        # does the entry match the rule "14"? If not, go to the next one
        if (e2["objectTypeAttributeId"] != 14):
            continue
        # print the current entry's associated value
        for attr in e2["objectAttributeValues"]
            print(attr["displayValue"])

【讨论】：

这似乎不是递归层次结构，不需要递归搜索。
@Barmar 是的，更新了一个更简单的解决方案的答案。谢谢：）

【解决方案2】：

如果结构没有改变那么这就是解决方案它将遍历所有对象并在search_values列表中添加displayValue

display_values = []
for object_entries in output_dict.get("objectEntries", []):
    for attribute in object_entries.get("attributes"):
        if attribute.get("objectTypeAttributeId") == "14":
            for object_attr in attribute.get("objectAttributeValues", []):
                if object_attr.get("displayValue") not in display_values:
                    display_values.append(object_attr.get("displayValue"))


print(display_values)

【讨论】：