如何动态命名数据框？

Question

假设我有一个数据框如下：

s = df.head().to_dict()
print(s)

{'BoP transfers': {1998: 12.346282212735618,
  1999: 19.06438060024298,
  2000: 18.24888031473687,
  2001: 24.860019912667006,
  2002: 32.38242225822908},
 'Current balance': {1998: -6.7953,
  1999: -2.9895,
  2000: -3.9694,
  2001: 1.1716,
  2002: 5.7433},
 'Domestic demand': {1998: 106.8610389799729,
  1999: 104.70302507466538,
  2000: 104.59254229534136,
  2001: 103.83532232336977,
  2002: 102.81709401489702},
 'Effective exchange rate': {1998: 88.134,
  1999: 95.6425,
  2000: 99.927725,
  2001: 101.92745,
  2002: 107.85565},
 'RoR (foreign liabilities)': {1998: 0.0433,
  1999: 0.0437,
  2000: 0.0542,
  2001: 0.0539,
  2002: 0.0474},
 'Gross foreign assets': {1998: 19.720897432405103,
  1999: 22.66200738564236,
  2000: 25.18270679890144,
  2001: 30.394226651732836,
  2002: 37.26477320359688},
 'Gross domestic income': {1998: 104.9037939043707,
  1999: 103.15361867816479,
  2000: 103.06777792080423,
  2001: 102.85886528974339,
  2002: 102.28518242008846},
 'Gross foreign liabilities': {1998: 60.59784839338306,
  1999: 61.03308220978983,
  2000: 64.01438055825233,
  2001: 67.07798172469921,
  2002: 70.16108592109364},
 'Inflation rate': {1998: 52.6613,
  1999: 19.3349,
  2000: 16.0798,
  2001: 15.076,
  2002: 17.236},
 'Credit': {1998: 0.20269913592846378,
  1999: 0.2154280880177353,
  2000: 0.282948948505006,
  2001: 0.3954812893893278,
  2002: 0.3578263032373988}}

可以使用以下方法将其转换回其原始形式：

df = pd.DataFrame.from_dict(s)

我对动态命名数据帧感兴趣，例如：

dim = df.shape[1]

counter1 = 0
counter2 = 1

while(counter1 <= dim):
   df_str(counter2) = df.iloc[:, counter1: (counter1 + 3)]
   counter1 = counter1 + 3
   counter2 = counter2 + 1

显然这段代码是错误的，不会起作用。但基本上我需要以 df_1、df_2、df_3 等结尾，具体取决于数据帧的列数。我在许多帖子中读到这是不好的做法，可以使用字典来完成；但这对我来说并不清楚。非常感谢一些指导。

Answer 1

i = 0
res = []
while i < df.shape[1]:
    res.append(df.iloc[:, i: (i + 3)])
    i = i + 3
print(res[0])
print(res[1])