比较键：- 嵌套字典列表

Question

我想编写一个函数来检查 dict1（基本字典）的键并将其与 dict2（嵌套字典列表，可以是一个或多个）的键进行比较，以便它检查强制键，然后检查可选键（如果和无论存在什么）并将差异作为列表返回。

dict1 = {"name": str,                    #mandatory
        "details" : {                    #optional
            "class" : str,               #optional 
            "subjects" : {               #optional
                "english" : bool,        #optional
                "maths" : bool           #optional
            }
        }}

dict2 = [{"name": "SK",
        "details" : {
            "class" : "A"}
         },
         {"name": "SK",
        "details" : {
            "class" : "A",
            "subjects" :{
                "english" : True,
                "science" : False
            }
        }}]

将 dict2 与 dict1 进行比较后，预期输出为：-

pass          #no difference in keys in 1st dictionary
["science"]    #the different key in second dictionary of dict2

Answer 1

试试这个递归检查函数：

def compare_dict_keys(d1, d2, diff: list):
    if isinstance(d2, dict):
        for key, expected_value in d2.items():
            try:
                actual_value = d1[key]
                compare_dict_keys(actual_value, expected_value, diff)
            except KeyError:
                diff.append(key)
    else:
        pass

字典 1 与字典 2

difference = []
compare_dict_keys(dict1, dict2, difference)
print(difference)

# Output: ['science']

dict2 与 dict1

difference = []
compare_dict_keys(dict2, dict1, difference)
print(difference)

# Output: ['maths']

Answer 2

转换成data frame并进行右反连接