SQL Oracle 错误：ORA-00907：缺少右括号答案

【问题标题】：SQL Oracle Error: ORA-00907: missing right parenthesisSQL Oracle 错误：ORA-00907：缺少右括号
【发布时间】：2018-07-18 17:43:14
【问题描述】：

Select m.CEAREGA, m.Crotal, rem.IdRexistro, m.IdMostraExt,
to_char(m.DataEntrega, 'DD/MM/YYYY') As Entrada, e.Descricion AS Ensaio,
to_char(rem.DataValidacion, 'DD/MM/YYYY') as DataValidacion, r.Descricion as Resultado, 
to_char(rem.Valor) as Valor, es.Descricion as Especie, tm.Descricion as Mostra,

(select LISTAGG(mo.Descricion, ':::') WITHIN GROUP (order by mo.Descricion)
from motivo_ensaio_mostra mm
join motivo_ensaio mo on mo.CodMotivo=mm.CodMotivo and mm.codLab=mo.codLab
where mm.IdRexistro=rem.IdRexistro and mm.IdMostra=rem.IdMostra and mm.CodLab=rem.CodLab
group by mm.IdRexistro, mm.IdMostra) as Motivo,

(select LISTAGG(trim(remi.NomeDesc || ' ' || remi.PrimeiroApelido || ' ' || remi.SegundoApelido), ':::') 
WITHIN GROUP (order by remi.PrimeiroApelido, remi.SegundoApelido, remi.NomeDesc)
from rexistro_remitente rm
join remitente remi on remi.NIFCIF=rm.NIFCIF and rm.codLab=remi.codLab
where rm.IdRexistro=rem.IdRexistro and rm.CodLab=rem.CodLab
group by rm.IdRexistro) as Remitente

from resultado_ensaio_mostra rem
join resultado r on r.CodResult=rem.CodResult and r.codLab = rem.codLab and r.CODTIPORESULT='P'
join mostra m on m.IdRexistro=rem.IdRexistro and m.IdMostra=rem.IdMostra and m.codLab = rem.codLab 
and m.VlxBaixa=0 and m.EstadoMostra<>10330004 and LENGTH(m.Crotal<5) and m.IdMostra > 201800000
join especie es on es.CodEspec=m.CodEspec and es.codLab = m.codLab
join tipo_mostra tm on tm.CodTipoMost=m.CodTipoMost and tm.codLab = m.codLab

显示 Oracle 错误：ORA-00907

我找不到缺少的括号或错误在哪里。谁能帮帮我？

提前致谢。

【问题讨论】：

删除半查询。再试一次等。
LENGTH(m.Crotal<5) 应该是LENGTH(m.Crotal)<5。
如果您的查询格式正确，您找到错误的机会会大得多

标签： sql oracle oracle11g ora-00907

【解决方案1】：

多么丑陋的代码；试着习惯它的格式，这样维护起来更容易。

无论如何：错误来自AND LENGTH (m.Crotal < 5) 行。

【讨论】：

【解决方案2】：

更改格式样式可能会有所帮助。

对于子查询，我尝试保持左括号和右括号明显地相互关联。我倾向于将它们放在同一列中，并将子查询的内容缩进。

同样，使每个谓词或计算彼此清楚地分开。我更喜欢将它们放在单独的行上，这样代码会更长，但代码会更窄；这对于diff （以及git）等工具更加友好。

这为我提供了以下内容，我可以比您的示例更快地进行可视化调试。 （事实上，我会说我无法直观地调试你的，每个单独的行或表达式都很难隔离和解析。）

SELECT
  m.CEAREGA,
  m.Crotal,
  rem.IdRexistro,
  m.IdMostraExt,
  to_char(m.DataEntrega, 'DD/MM/YYYY') As Entrada,
  e.Descricion AS Ensaio,
  to_char(rem.DataValidacion, 'DD/MM/YYYY') as DataValidacion,
  r.Descricion as Resultado, 
  to_char(rem.Valor) as Valor,
  es.Descricion as Especie,
  tm.Descricion as Mostra,
  (
    select
      LISTAGG(mo.Descricion, ':::')
        WITHIN GROUP (order by mo.Descricion)
    from
      motivo_ensaio_mostra mm
    join
      motivo_ensaio mo
        on  mo.CodMotivo=mm.CodMotivo
        and mm.codLab=mo.codLab
    where
          mm.IdRexistro=rem.IdRexistro
      and mm.IdMostra=rem.IdMostra
      and mm.CodLab=rem.CodLab
    group by
      mm.IdRexistro, mm.IdMostra
  ) as Motivo,
  (
    select
      LISTAGG(trim(remi.NomeDesc || ' ' || remi.PrimeiroApelido || ' ' || remi.SegundoApelido), ':::') 
        WITHIN GROUP (order by remi.PrimeiroApelido, remi.SegundoApelido, remi.NomeDesc)
    from
      rexistro_remitente rm
    join
      remitente remi
        on  remi.NIFCIF=rm.NIFCIF
        and rm.codLab=remi.codLab
    where
          rm.IdRexistro=rem.IdRexistro
      and rm.CodLab=rem.CodLab
    group by
      rm.IdRexistro
  ) as Remitente
from
  resultado_ensaio_mostra rem
join
  resultado r
    on  r.CodResult = rem.CodResult
    and r.codLab = rem.codLab
    and r.CODTIPORESULT='P'
join
  mostra m
    on  m.IdRexistro = rem.IdRexistro
    and m.IdMostra = rem.IdMostra
    and m.codLab = rem.codLab 
    and m.VlxBaixa=0
    and m.EstadoMostra<>10330004
    and LENGTH(m.Crotal<5)
    and m.IdMostra > 201800000
join
  especie es
    on  es.CodEspec=m.CodEspec
    and es.codLab = m.codLab
join
  tipo_mostra tm
    on  tm.CodTipoMost=m.CodTipoMost
    and tm.codLab = m.codLab

这使我得出结论，括号不是问题。所以，很可能是括号附近的一些其他语法错误。

根据我在重新格式化您的代码时出现的答案，它似乎是 LENGTH(m.Crotal<5) 应该是 LENGTH(m.Crotal) < 5？

（本质上，< 之前缺少一个)，而5 之后还有一个额外的...）

【讨论】：