如何使用 STUFF 和 FOR XML PATH 分隔与其行相关的唯一值答案

【问题标题】：How to separate unique values respective to its row using STUFF and FOR XML PATH如何使用 STUFF 和 FOR XML PATH 分隔与其行相关的唯一值
【发布时间】：2020-12-02 06:49:09
【问题描述】：

我正在运行这个查询：

SELECT A.PeripheralNumber, P.LoginName, P.FirstName, P.LastName, A.EnterpriseName, A.AgentDeskSettingsID, AttributeValues = 
STUFF((SELECT ',' + ATT.EnterpriseName+'='+AT.AttributeValue AS Attribute
FROM Agent_Attribute AT
LEFT JOIN Agent A ON A.SkillTargetID = AT.SkillTargetID
LEFT JOIN Attribute ATT ON ATT.AttributeID = AT.AttributeID
WHERE A.SkillTargetID IN ('26379','24111')
ORDER BY Attribute
FOR XML PATH (''), TYPE ).value('.', 'VARCHAR(MAX)'), 1, 1, '')
FROM Agent A
LEFT JOIN Person P ON P.PersonID = A.PersonID
LEFT JOIN Agent_Desk_Settings ADS ON ADS.AgentDeskSettingsID = A.AgentDeskSettingsID
WHERE A.SkillTargetID IN ('26379','24111')
AND A.EnterpriseName LIKE 'PG_8%'
AND P.FirstName NOT LIKE '%Test%'
GROUP BY A.PeripheralNumber, P.LoginName, P.FirstName, P.LastName, A.EnterpriseName, A.AgentDeskSettingsID

我得到的结果如下：

|PeripheralNumber|LoginName|FirstName|LastName|EnterpriseName|AgentDeskSettingsID|AttributeValues                                                                                                 |
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
|551628          |551628   |John     |Doe     |Doe_John      |5104               |AAH_CSC_EXIST=5,AAH_CSC_FNOL=5,AAH_CSC_ROTL=5,AAH_SERVICE_AUTO=10,AAH_SERVICE_REBRAND=5,AAH_SERVICE_WEB_ONLINE=10|
|558792          |558792   |Jane     |Doe     |Doe_Jane      |5103               |AAH_CSC_EXIST=5,AAH_CSC_FNOL=5,AAH_CSC_ROTL=5,AAH_SERVICE_AUTO=10,AAH_SERVICE_REBRAND=5,AAH_SERVICE_WEB_ONLINE=10|
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

目前正在合并 John Doe 和 Jane Doe 的唯一 AttributeValues。我需要的结果如下：

|PeripheralNumber|LoginName|FirstName|LastName|EnterpriseName|AgentDeskSettingsID|AttributeValues                                                                                                 |
------------------------------------------------------------------------------------------------------------------------------------------------------
|551628          |551628   |John     |Doe     |Doe_John      |5104               |AAH_SERVICE_AUTO=10,AAH_SERVICE_REBRAND=5,AAH_SERVICE_WEB_ONLINE=10|
|558792          |558792   |Jane     |Doe     |Doe_Jane      |5103               |AAH_CSC_EXIST=5,AAH_CSC_FNOL=5,AAH_CSC_ROTL=5                      |
------------------------------------------------------------------------------------------------------------------------------------------------------

帮助！这是 MS SQL Server 2016

【问题讨论】：

从不在 FROM 子句中使用逗号。始终使用正确、明确、标准、可读的JOIN语法。
@GordonLinoff，我已经更新了上面的查询以包含 JOINS...仍然得到相同的结果
。 .尽管可以发现错误的人会回答，但更有可能。

标签： sql sql-server xml sql-server-2016 stuff

【解决方案1】：

你 cross apply 或 outer apply。像这样的：

SELECT DISTINCT A.PeripheralNumber, P.LoginName, P.FirstName, P.LastName, A.EnterpriseName, A.AgentDeskSettingsID, DS.AttributeValues
FROM Agent A
LEFT JOIN Person P
    ON A.PersonID = P.PersonID
LEFT JOIN Agent_Desk_Settings ADS
    ON A.AgentDeskSettingsID = ADS.AgentDeskSettingsID
OUTER APPLY
(
    SELECT STUFF((SELECT ',' + ATT.EnterpriseName+'='+AT.AttributeValue AS Attribute
    FROM Agent_Attribute AT
    INNER JOIN Attribute ATT
        ON ATT.AttributeID = AT.AttributeID
    WHERE A.SkillTargetID = AT.SkillTargetID
    ORDER BY Attribute
    FOR XML PATH (''), TYPE ).value('.', 'VARCHAR(MAX)'), 1, 1, '')
) DS (AttributeValues)
WHERE A.SkillTargetID IN ('26379','24111')
    AND A.EnterpriseName LIKE 'PG_8%'
    AND P.FirstName NOT LIKE '%Test%'

【讨论】：

【解决方案2】：

如果要将值限制为单个人，则需要关联该人：

STUFF((SELECT ',' + ATT.EnterpriseName+'='+AT.AttributeValue AS Attribute
       FROM Agent_Attribute AT JOIN
            Agent A 
            ON A.SkillTargetID = AT.SkillTargetID
            Attribute ATT
            ON ATT.AttributeID = AT.AttributeID
            WHERE A.SkillTargetID IN (26379, 24111) AND
                  AA.PersonID = p.PersonId
            ORDER BY Attribute
            FOR XML PATH (''), TYPE
           ).value('.', 'VARCHAR(MAX)'), 1, 1, '')

请注意，我删除了看起来像数字常量的单引号。如果这些确实是字符串，则包括单引号。

另外，LEFT JOINs 在相关子查询中是多余的。

【讨论】：