【发布时间】:2022-11-02 21:06:52
【问题描述】:
我想在 3 个物种(大鼠、斑马鱼和 pupfish)中做一个相同肽的 msa,并将它与我拥有的 2 个合成肽(M35 和 M871)匹配(发现相同的身份/差异),但我得到以下构建向量后的错误:
Library (ggmsa)
galanin_table <- c("MACSKHLVLFLTILLSLAETPDSAPAHRGRGGWTLNSAGYLLGPVLHLSSKANQGRKTDSALEILDLWKAIDGLPYSRSPRMTKRSMGETFVKPRTGDLRIVDKNVPDEEATLNL", "Rat", "MHRCVGGVCVSLIVCAFLTETLGMVIAAKEKRGWTLNSAGYLLGPRRIDHLIQIKDTPSARGREDLLGQYAIDSHRSLSDKHGLAGKREMPLDEDFKTGALRIADEDVVHTIIDFLSYLKLKEIGALDSLPSSLTSEEISQP", "Zebrafish", "MQRSFAVFCVSLIFCATLSETIGLVIAAKEKRGWTLNSAGYLLGPRRIDHLIQIKDSPSARGRDELVNQYGIDGHRTLGDKAGLAGKRDMAQEDDVRTGPLRIGDEDIIHTVIDFLSYLKLKEMGALDSLPSPLTSDELANP", "Pupfish", "GWTLNSAGYLLGPPPGFSPFR","M35", "WTLNSAGYLLGPEHPPPALALA","M871")
galanin_matrix <- matrix(galanin_table, byrow=T, nrow=5)
galanin_table <- as.data.frame(galanin_matrix, stringsAsFactors = F)
colnames(galanin_table) <- c("Sequences", "Species")
galanin_table <- as.data.frame(galanin_table)
galanin_list <- as.list(galanin_table)
galanin_asvector <- as.vector(galanin_list)
galanin_asvector_ss <- Biostrings::AAStringSet(x= galanin_asvector)
(函数(类,fdef,mtable)中的错误: 无法为签名“字符”找到函数“seqtype”的继承方法
可能我以错误的方式构建向量
【问题讨论】:
标签: r bioinformatics