TypeError: 只能将 str（而不是 \"tuple\"）连接到 str

Question

我正在尝试制作密码生成器。我收到错误：TypeError: can only concatenate str (not "tuple") to str

我试过的：

原来的

def generate():
    lbl.config(text = "Password Generated: " + password)

已编辑（仍然无法正常工作）

def generate():
    lbl.config(text = ("Password Generated: " + password))

这是完整的脚本：

#imports
import tkinter as tk
import string
import random

#Password Generator
c1 = random.choice(string.ascii_letters)
c2 = random.choice(string.ascii_letters)
c3 = random.choice(string.ascii_letters)
c4 = random.choice(string.ascii_letters)
c5 = random.choice(string.ascii_letters)
c6 = random.choice(string.ascii_letters)
c7 = random.choice(string.ascii_letters)
c8 = random.choice(string.ascii_letters)
c9 = random.choice(string.ascii_letters)
c10 = random.choice(string.ascii_letters)
s1 = random.choice(string.punctuation)
n1 = random.randint(0,9)
n2 = random.randint(0,9)
n3 = random.randint(0,9)

password = (c1, c2, c3, c4, c5, c6, c7, c8, c9, c10, s1, n1, n2, n3)

#Setting up Window
frame = tk.Tk()
frame.title("Random Password Generator")
frame.geometry("1280x720")

#Label
lbl = tk.Label(frame, text = " ")
lbl.pack()
frame.mainloop()

#Function : Generator
def generate():
    lbl.config(text = ("Password Generated: " + password))
    
#Button - Generate
genButton = tk.Button(frame,
                        text = "Generate",
                        command = generate())
genButton.pack()

#execute1

generate()

Answer 1

该错误是有道理的，因为您试图将str 对象与tuple 对象连接起来。

def generate():
    lbl.config(text = ("Password Generated: " + password))
                       ^^^^^^^^^^^^^^^^^^^^     ^^^^^^^^^
                                |                    |
                                |                    |
                               String object        Tuple object

我认为您打算从元组创建一个字符串对象，您可以使用 .join 方法来完成。

def generate():
        lbl.config(text = ("Password Generated: " + "".join(str(p) for p in password))) 
                                                   ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^