特定的 MySql 查询

Question

有以下表格

Post(*id, name, description, cat, publish_date)
Category(*id, name)

可以在一个查询中获取（最大）每个不同类别的前 N ​​个元素吗？

假设 N=3，我需要以下结果：

结果集：

["1", "Name1","Descr","cat1"]
["2", "Name1","Descr","cat1"]
["3", "Name1","Descr","cat1"]
["10","Name1","Descr","cat2"]
["20","Name1","Descr","cat2"]
["22","Name1","Descr","cat2"]
["25","Name1","Descr","cat3"]
["30","Name1","Descr","cat3"]
["19","Name1","Descr","cat3"]

等等。

我需要这个，以获取每个类别的前 N ​​篇文章，通过一个查询（因此不要求特定类别，而是表中的所有类别）

有可能吗？如果是，那么正确的查询是什么？

Answer 1

您可以使用UNION 将多个查询合并为一个。这假设您知道您为每个集合选择的type。

SELECT * FROM 
(
  SELECT * FROM T1 WHERE type='Type1' ORDER BY id DESC LIMIT 3
) DUMMY1

UNION ALL

SELECT * FROM 
(
  SELECT * FROM T1 WHERE type='Type2' ORDER BY id DESC LIMIT 3
) DUMMY2

UNION ALL

SELECT * FROM 
(
  SELECT * FROM T1 WHERE type='Type3' ORDER BY id DESC LIMIT 3
) DUMMY3

allow ordering within each subquery 需要 DUMMY 表别名。

Answer 2

此查询将满足您的需求。如果任何类别的帖子少于 3 个，它仍然有效。

SELECT P.id,P.name,P.description,C.name 
FROM Post P
LEFT JOIN Category C
ON P.type = C.id
WHERE FIND_IN_SET(P.id,
    (
        SELECT GROUP_CONCAT(ids) FROM
            (SELECT SUBSTRING_INDEX(GROUP_CONCAT(id),',',3) as ids
                FROM Post 
                GROUP BY type
            ) AS foo
        GROUP BY ''
    )
)

这是一个有效的SQL Fiddle

更新

回应您的评论和更新的问题：

SELECT P.id,P.name,P.description,P.publish_date,C.name 
FROM Post P
LEFT JOIN Category C
ON P.type = C.id
WHERE FIND_IN_SET(P.id,
    (
        SELECT GROUP_CONCAT(ids) FROM
            (SELECT SUBSTRING_INDEX(GROUP_CONCAT(id ORDER BY publish_date DESC),',',3) as ids
                FROM Post
                GROUP BY type      
            ) AS foo
        GROUP BY ''
    )
)