【问题标题】:It is curious to convert Mysql to Oracle [duplicate]将Mysql转换为Oracle很奇怪[重复]
【发布时间】:2016-01-27 18:03:40
【问题描述】:

这是mysql代码。

UPDATE ORDER_ITEM OI
INNER JOIN ORDER_PAYMENT OP
ON OI.ORDER_PAYMENT_ID = OP.ORDER_PAYMENT_ID
SET OI.ORDER_STATUS    = '10',
  OI.PAY_DATE          = '20150101',
  OP.PAY_DATE          = '20150101'
WHERE OI.ORDER_STATUS        = '0'
AND OP.AMOUNT                = 3333
AND OP.REMAINING_AMOUNT      = 0
AND OP.ORDER_PAYMENT_ID      = 9999 

转换 Oracle 错误 => ORA-00971:缺少 SET 关键字

我想知道如何将此语句转换为 Oracle。

PS。 Oracle 中可用的多表更新?

【问题讨论】:

标签: mysql oracle


【解决方案1】:

Oracle 绝对不允许在一个 SQL 语句中更新两个表。因此,您的案例需要 3 个陈述:

-- This query locks target rows in both tables.
-- It's required to be sure that rows wasn't changed in other sessions
-- between the first and second UPDATE statements
SELECT *
  FROM order_item oi
 INNER JOIN order_payment op
    ON oi.order_payment_id = op.order_payment_id    
 WHERE oi.order_status = '0'
   AND op.amount = 3333
   AND op.remaining_amount = 0
   AND op.order_payment_id = 9999
   FOR UPDATE NOWAIT

-- first update
UPDATE order_item
   SET order_status = '10',
       pay_date = '20150101'
 WHERE rowid IN (SELECT oi.rowid
                      FROM order_item oi
                     INNER JOIN order_payment op
                        ON oi.order_payment_id = op.order_payment_id                                
                     WHERE oi.order_status = '0'
                       AND op.amount = 3333
                       AND op.remaining_amount = 0
                       AND op.order_payment_id = 9999);

--second update
UPDATE order_payment
   SET pay_date = '20150101'
 WHERE rowid IN (SELECT op.rowid
                      FROM order_item oi
                     INNER JOIN order_payment op
                        ON oi.order_payment_id = op.order_payment_id                                
                     WHERE oi.order_status = '0'
                       AND op.amount = 3333
                       AND op.remaining_amount = 0
                       AND op.order_payment_id = 9999);

使用 PL/SQL 我们可以稍微简化此代码,但我们仍然必须编写一个 SELECT FOR UPDATE 并为每个连接的表编写一个 UPDATE。

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