【发布时间】:2022-09-27 20:39:52
【问题描述】:
我想编写一个代码,根据衣物的重量计算洗衣费用。我希望它在 4 次输入后停止并计算当天的总销售额。我似乎无法正确打印输出,它继续为所有输出打印 0。
#include<stdio.h>
int main() {
printf(\"\\t\\tWELCOME TO UNIMAP LAUNDRY\");
printf(\"\\nThis program is to display laundry price paid by customers\\n\");
float l, W, sum, r;
for (l = 0; l < 4; l++) {
printf(\"Please enter laundry weight(kg):\");
scanf(\"%f\", & W);
printf(\"Total amount to pay is RM%f\\n\", r);
if (W < 1)
r == (W * 1.2);
else if (W < 7)
r == (W * 0.9);
else if (W < 12)
r == (W * 0.6);
else
r == (W * 0.7);
}
sum += r;
printf(\"The total sales are RM%f\", sum);
return 0;
}
我得到的输出示例:
WELCOME TO UNIMAP LAUNDRY
This program is to display laundry prices paid by customers
Please enter laundry weight(kg):12
The total amount to pay is RM0.000000
Please enter laundry weight(kg):6
The total amount to pay is RM0.000000
Please enter laundry weight(kg):5
The total amount to pay is RM0.000000
Please enter laundry weight(kg):9
The total amount to pay is RM0.000000
The total sales are RM-29726079709203136512.000000
-
请缩进您的代码以使其可读。
-
帮自己一个忙,正确缩进你的代码。使用不明代码非常困难,即使对于顶级程序员来说,更不用说初学者了。还要使用有意义的变量名,而不是
W、l等。 -
您可能希望将打印“Total amount to pay”的行移到循环末尾;
sum变量应该被初始化,sum=0,并且sum += r;行也应该被移动到循环内。
标签: c