在 Python 中以交互模式运行 playwright答案

【问题标题】：Run playwright in interactive mode in Python在 Python 中以交互模式运行 playwright
【发布时间】：2022-08-22 02:57:31
【问题描述】：

我正在使用剧作家使用 Python 来抓取页面。我知道如何使用脚本来做同样的事情，但我是在交互模式下尝试的。

from playwright.sync_api import Playwright, sync_playwright, expect
import time

def run(playwright: Playwright) -> None:
    browser = playwright.chromium.launch(headless=False)
    context = browser.new_context()

    page = context.new_page()
    page.goto(\"https://www.wikipedia.org/\")

    context.close()
    browser.close()
with sync_playwright() as playwright:
    run(playwright)

我试图在交互模式下这样做：

>>> from playwright.sync_api import Playwright, sync_playwright, expect
>>> playwright = sync_playwright()
>>> browser = playwright.chromium.launch(headless=False)

但这给了我一个错误：

Traceback (most recent call last):
  File \"C:\\Users\\hpoddar\\AppData\\Local\\Programs\\Python\\Python310\\lib\\idlelib\\run.py\", line 578, in runcode
    exec(code, self.locals)
  File \"<pyshell#2>\", line 1, in <module>
AttributeError: \'PlaywrightContextManager\' object has no attribute \'chromium\'

与 sync_playwright() as playwright: 不一样 \"playwright = sync_playwright()\" 。 playwright 对象仅在 \"with\" docs.python.org/3/reference/datamodel.html#context-managers 打开的上下文管理器内部有效
@PmpP。查看 Charchit 的答案，这正是我需要的 stackoverflow.com/a/73271105/10216112

标签： python web-scraping chromium playwright playwright-python

【解决方案1】：

使用.start() 方法：

>>> from playwright.sync_api import Playwright, sync_playwright, expect
>>> playwright = sync_playwright().start()
>>> browser = playwright.chromium.launch(headless=False)
>>> page = browser.new_page()

或者，如果您只想要一个交互式浏览器，而不关心交互式 shell，您也可以使用 wait_for_timeout 函数（仅适用于 Page 对象）并将超时设置为高值：

from playwright.sync_api import sync_playwright

with sync_playwright() as playwright:
    browser = playwright.chromium.launch(headless=False)
    page = browser.new_page()
    page.wait_for_timeout(10000)

【讨论】：

有没有像sync_playwright().stop() 这样的方法？
@Himanshuman 就做playwright.stop()